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Texas Jigsaw Killer 21

 
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PsyMar
Hooked
Hooked


Joined: 17 Nov 2006
Posts: 32
Location: The Triad, North Carolina, US

PostPosted: Thu Dec 21, 2006 4:51 pm    Post subject: Texas Jigsaw Killer 21 Reply with quote

Whoo. First try on this one fizzled, came back a few days later (that is, today.) Took a good couple hours but I've got a walkthrough.

Code:

0.  Nonet numbering:
112222233
111222333
411123336
441555366
444555666
447555966
477789996
777888999
778888899



1. cagesize/sum eliminations:
1a. 6/3 in N8 = {123} naked triple in N8
1b. digits in 8/3s in N3, N6/R5 and N7 <= 5, must have 1 -> no other 1s in N3, N6, R5, and N7
1c. digits in 9/3 in N4 <= 6
1d. digits in 10/3s in N5 and N9 <= 7
1e. digits in 11/3 in N2 <= 8
1f. digits in 19/3 in N4 >= 2
1g. digits in 20/3 in N7 >= 3
1h. digits in 21/3s in N5 and N9 >= 4
1i. 24/3s in N3 and N6 = {789} naked triples in N3 and N6

2. Innies of R5 = R5C456 = 20 -> R5C456 != 1|2
3. 6s in N36 locked in C89 -> not in rest of C89
4. 1s of N4789 locked in R6789 -> no 1s in rest of R6789
5. 1 of N5 locked in R4 -> not in rest of R4
6. 1 of N3689 locked in C6789 -> not in rest of C6789
7. 19/3 in C5 = {469|478|568} -> 10/3 in C5 != {145} -> no 4 in 10/3 in C5
8. 19/3 in C5 = {469|478|568} -> 16/3 in C5 != {268|367|457} -> 16/3 in C5 = {169|178|259|349|358}
9. LOL: R37C6 == R19C7; R3C6 != R9C7 -> R3C6 == R1C7 && R7C6 == R9C7 -> R1C7 = {789} && R7C6 = {123}
10. R789C6 = naked triple {123} on C6
11. R134C7 = naked triple {789} on C7
12. 21/3 in N9 = {489|579|678}; R8C7 = {456} -> R78C8 = {78|79|89}
13. R678C8 = naked triple {789} on C8
14. LOL: R3C19 == R4C37; R3C9!=R4C7 -> R3C9 == R4C3 && R3C1 == R4C7 -> R3C1 = {789} && R4C3 = {23456}
15. R3C167 = naked triple {789} on R3
16. 7s, 8s, and 9s of R345 locked in N345 -> not in rest of N345
17. R6C389 = hidden triple {789}
18. 10/3 in N9 = {136|145|235} -> 14/3 in N9 != {158|347} -> 14/3 in N9 = {149|239|248|257}
19. 8/3 in R5 = {125|134} -> 17/3 in R5 != {359|458} -> 17/3 in R5 = {269|278|368|467} -> no 5 in 17/3 in R5
20. 1 of N4 locked in 9/3 -> 9/3 = {126|135} -> 19/3 in N4 != {568} -> no 5 in 19/3 in N4 -> 5 of N4 locked in 9/3 -> 9/3 in N4 = {135} naked triple
21. How'd I miss this before -- outies of R12 = R3C258 = 6/3 = {123} naked triple in R3
22. combinations for 15/3 in N1 = {456} naked triple in N1
23. Innies of R6789 = R6C456 = 12/3 with max 6 = {156|246|345} but {156|345} conflict with 9/3 in N4 so R6C456 = {246} naked triple in R6/N5
24. 18/3 in N2 with min 4 has exactly one of {789}, R1C7 = {789} -> not in rest of 18/3 in N2
25. R126C6 = naked triple {456} in C6
26. innies of R5 = R5C456 = 20/3 -> even number of odd digits -> odd number of even digits -> must contain 8, elim 8 from rest of R5/N5
27. 8 of N4 locked in 19/3 -> 19/3 = {289|478} -> no 6 in 19/3 in N4
28. 6 of C12 locked in N47 -> not in rest of N47
29. 17/3 in N7 = {278|359|458} -> contains either 2 or 5 -> 8/3 in N7 != {125} -> 8/3 in N7 = {134} naked triple -> 17/3 in N7 = {278} naked triple -> 20/3 in N7 = {569}
30. 2 of N7 locked in R7 -> not in rest of R7
31. 10/3 in N9 = {136|145} -> 10/3 has either 4 or 6, both of which can only be in R7C7 -> R7C7 = {46}
32. 21/3 in C6 = {489|678} -> must contain 8 -> R5C6 = 8
33. 5 of C6 locked in N2 -> not in rest of N2
34. 4 of C1 locked in N4 -> not in rest of N4
35. 4 of C2 locked in N7 -> not in rest of N7
36. R7C3489 = naked quad {2789} in R7
37. LOL -> R37C6 == R19C7 -> R1C7 = {79} and R9C7 = {13}
38. 18/3 in N2 = {459|567} -> 18/3 has either 4 or 6 -> 11/3 in N2 != {146} -> no 4 in 11/3 in N2
39. 16/3 in N2: R3C5 = {123} -> no 1|2|3 in rest of 16/3
40. 9 of R6 locked in N6 -> not in rest of N6
41. R7C8 = 9 (hidden single)
42. R6C9 = 9 (hidden single)
43. 21/3 in N9 = [948|957] -> no 6 in 21/3 in N9
44. R7C7 = 6 (hidden single)
45. 10/3 in N9 = {136} naked triple in N9
46. 5 of R6 locked in N4 -> not in rest of N4
47. R7C16 = naked pair {13} in R7 -> R7C2 = 4 -> R7C5 = 5
48. R8C23 = naked pair {13} in R8 -> R8C6 = 2
49. R69C7 = naked pair (13) in C7
50. outies of C12 = R258C3 = 13/3 = [193|391|823]
51. combinations for 17/3 in R5 = {269} naked triple -> 19/3 in N4 = {478} && 8/3 in R5 = {134} naked triple && R5C7 = 4 -> lots of naked and hidden singles and last-digit-in-cage moves solve it.

Final solution:
382195746
791846253
826437915
475319862
269578431
537624189
148253697
613982574
954761328


That was fun!
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