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rcbroughton
Expert

Joined: 15 Nov 2006
Posts: 143
Location: London

 Posted: Fri Jul 20, 2007 7:52 pm    Post subject: Assassin 60 Plugged away at this one to a solution: a. Cage 21(3) n3 no 1/2/3 0b. Cage 9(3) n124 no 7/8/9 0c. Cage 11(3) n4 no 9 0d. Cage 10(3) n568 and 10(3) n89 - no 8/9 0r. Cage 20(3) n9, 20(3) n7, 20(3) n8 - no 1,2 1. 6(3) n1={123} locked for n1 2. 22(3) n1 no 1/2/3/4 - must use 9 - locked for n1 3. 45 Rule on n3 - innies r3c789 total 10 = {127}/{136}/{145}/{235} - no 8,9 3a. 16(3) n36 means r3c89 can't be {12}/{13}/{14}/{15}/{23}/{27} 3b. r3c7 to can't be 4, 5, 6 or 7 4. 45 Rule on n7 - innies r789c3 total 9 = {126}/{135}/{234} - no 7/8/9 4a. 13(3) n78 means r89c3 can't be {12} 4b. no 6 at r7c3 5. 45 Rule on n3 - outies r4c9 minus innies r3c7 equals 6 -> r4c9 = 7/8/9 6. 45 Rule on n7 - outies r9c4 minus innies r7c3 equals 4 - no 1/2/3/4 in r9c4 7. 45 Rule on c98 - innies r27c8 total 13 ={49}/{58}/{67} - no 3 at r7c8 8. 45 Rule on c123 - outies r39c4 minus innies r1c3 equals 2 - no 5/6 r3c4 9. 45 Rule on c6-9 - innies r15c6 total 13 = {49}/{58}/{67} - no 1/2/3 10. 45 Rule on n9 - innies r7c9 r9c7 total 9 - no 1/9 at r7c9 11. 45 Rule on r9876 - innies r6c15 total 7 - no 7/8/9 12. 15(3) n23 - {456} not valid 12a. r3c7 = 1/2/3 - can't be at r23c6 13. 9(3) n124 - {234} must have 4 at r3c3 so no 4 at r3c4 r4c3 13b. {126}/{135} - can't have 5/6 in r4c3 14. 17(3) n5 only combo with 1 requuires a 7 - only occurs in r5c5 - so no 1 at r5c5 15. 17(3) n47 - 1 requires {79}, 2 requires {69} or{78} - no 1/2 r6c23 16. 45 Rule on n4 - outies r3c1 r7c3 minus innies r4c3 equals 6 - no 6 at r3c1 17. 45 Rule on r89 - innies r8c27 total 11 - no 1/9 at r8c2 18. 45 Rule on n124 - outies r3c7 r7c3 total 4 - no 4/5 at r7c3 19. 45 Rule on n6985 - innies r4c9 r9c4 total 14 - no 8/9 at r9c4 Or the same elimination looking at innies/outies on n7 - as in step 6 20. 45 Rule on r12 - outies r3c2567 total 24 [Edit - don't need the extra 20a here]20b. no possibility with 1/2/3 at r3c5 21. 13(3) n2 - only combo with 9 is {139} - 9 must be at r3c5 - no 9 at r2c45 22. 17(3) n47 again - {467}/{458} can't be placed - no 4 22a. {359}/{368} need 3 at r3c3 - no 3 at r6c23 23. 45 Rule on n2 - outies r1c3 r3c7 minus innies r3c4 equals 6 - no 6 at r1c3 24. innies on n1 - r3c13 r1c3 = h17(3) =4{58}/4{67} 25. 45 Rule on n2 - outies r134c3 r3c7 total 15 25a. can't have [63] [41] at r34c3 because of cage sum for 9(3) n124 25b. h17(3) from 24 means r13c3 can't be [56] [74] [75] 25c. for r134c3=13 - [562]/[751]/[742] - blocked by 25b [841]/[463] blocked by 25a25d. can't make total 13 in r134c3 ( and [463]) - no 2 at r3c7 26. 45 Rule on n3 - outies r4c9 minus innies r3c7 equals 6 - no 8 at r4c9 27. 16(3) n36 - can't make a combo with 7 at r3c89 28. 45 Rule on n124 - outies r3c7 r7c3 total 4 - no 2 at r7c3 29. 45 Rule on n7 - outies r9c4 minus innies r7c3 equals 4 - no 6 at r9c4 30. 20(3)n8 - {578} blocked by r9c4 - remaining combos must use 9 - locked for n8 31. 13(3) n78 - can't place {346} because of r9c4 - ={157}/{247}/{256} - no 3 32. 45 Rule on r1 - innies r1c12789 total 22 32a. r1c12 totals 3, 4, 5 32b. r1c89 total 5,6,7,8,9,10,11,12,13 32c. r1c89 can't be {58} {47} {56} {37} {46} {45} - no valid combo in 14(3) 32d. can't make a combo with 8 at r1c7 preamble to step 33 14(3) n3 21(3)n3 blocks {158}/{347} h10(3) blocks {149} h10(3) and 21(3) blocks {356} 14(3) = {167}/{239}/{248}/{257} 33. 45 Rule on r1 - outies r2c1789 total 19 33a. r2c789 totals 16(no 3),17(no 2),18(no 1) 33b. r2c78 can only be: 12={75}/{84},14={68}/{95},15={78},16={79},17={89}33c. can't make combos with 7,8,9 at r2c9 33. 45 Rule on r1 - innies r1c7 minus outies r2c19 equals 2 - no 4 at r1c7 [should have been 34 - oops] 34. 45 Rule on c1 - innies r12789c1 total 22= 34a. r12c1 totals 3,4,5 34b. r789c1 totals 19,18,17 34c. r89c1 can't be {68} {48} {37} {46} {67} {45} because of cage sum in 20(3)n7 34d can't make a combo with 9 at r7c1 35. innies on r123 = r3c13489 = 21(5) 35a. c89 can only total 7 or 9 35b. c34 can only total 8,7 or 6 35c. {12369} -> can't be placed because of r3c1 35d. {12378} -> can't be placed because of r3c1 has only 7/8 35e. {12459} -> can't be placed - no 9 35f. {12468} -> [842]{16} 35g. {12567} -> [761]{25} 35h. {13458} -> blocked by r3c7 35i. {13467} - ditto 35j. {23457} -> [742]{35} 35k. no 4/5 r3c1, no 5 r3c3, no 3 r3c4, no {34} r3c89 36. Hidden single 3 at r3c7 36a. 15(3)=3{48}/{57} - no 6,9 37. 4 locked in c3 of n1 38. 9(3) n1 now = {126{/{234} - must use 2. -> no 2 at r4c4 39. 16(3) n3 now = {16}9/{25}9 - 9 placed at r4c9 40 13(3)n7={157}/{256} - must use 5 - no 5 at r9c12 41. 23(4)c1 - on;y combos with 1 also need a 9 - no 1 at r5c1 42 20(3)n7 - only combo with a 6 needs a 5 - no 6 at r8c1 43. from step 28 - r7c3 = 1 43a. 17(3)=1{79} - {79} locked for n4, r6 44. 3 locked in r45 for c3 - locked for n4 45. 23(4)c1= {2678}/{4568} - must use 68 locked for n4 and c1 45. 11(3)n4 now={128}/{245} - must use 2 locked for n4 45a. naked single 3 at r4c3 -> 9(3) = [423] 46. 16(3)n36 = {16}9 - {16} locked for n3, r3 47. hidden triple {456} at r456c1 -lcked for n4, r1 47a. -> 23(4) = 8{456} 48. hidden single 8 at r5c3 Rest is simple eliminations Still stumped with the Reject Version Rgds RichardLast edited by rcbroughton on Sun Jul 22, 2007 10:34 am; edited 1 time in total
CathyW
Master

Joined: 31 Jan 2007
Posts: 161
Location: Hertfordshire, UK

 Posted: Sat Jul 21, 2007 2:14 pm    Post subject: Edit: I have a problem with one of my early steps which affects the rest so have deleted the walkthrough. Hopefully will be able to rework it and post revised steps later.Last edited by CathyW on Mon Jul 23, 2007 6:45 pm; edited 2 times in total
mhparker
Grandmaster

Joined: 20 Jan 2007
Posts: 345
Location: Germany

 Posted: Sat Jul 21, 2007 8:03 pm    Post subject: Hi folks, I found this Assassin comparable in difficulty to last week's A59 V1.5, so I was surprised to see two walkthroughs posted already (congratulations Richard and Cathy!). Maybe it's because this Assassin was more susceptible to intensive innie/outie work. In my case, however, I ignored much of this information, and used a couple of interesting chains to gain a foothold instead. Therefore, I've decided to post my walkthrough, too. Now for the A60RP, if Richard hasn't finished it already... Assassin 60 Walkthrough 1. 6/3 at R1C1 = {123}, locked for N1 2. 21/3 at R1C7 = {489/579/678} (no 1,2,3) 3. 22/3 at R2C2 = {(58/67)9} (no 4) 3a. 9 locked for N1 4. 9/3 at R3C3 = {126/135/234} (no 7,8,9) 4a. needs 2 of {123}, only in R3C4+R4C3 4b. -> R3C4 = {123}, R4C3 = {123} 5. 11/3 at R4C2 = {128/137/146/236/245} (no 9) 6. 10/3 at R6C6 and R8C6 = {127/136/145/235} (no 8,9) 7. 20/3 at R7C7, R8C1 and R8C4 = {389/479/569/578} (no 1,2) 8. Innies N3: R3C789 = 10/3 = {127/136/145/235} (no 8,9) 9. Outies N124: R3C7+R7C3 = 4/2 9a. -> R3C7 = {123}, R7C3 = {123} 9b. -> min. R6C23 = 14 9c. -> no 1,2,3,4 in R6C23 10. I/O difference N3: R4C9 = R3C7 + 6 10a. -> R4C9 = {789} 11. Innies C89: R27C8 = 13/2 = {49/58/67} (no 3) 12. Outies R12: R3C2567 = 24/4 12a. max. R3C7 = 3 12b. -> min. R3C256 = 21 12c. -> no 1,2,3 in R3C56 12d. Cleanup: no 9 in R2C45 13. Killer Hidden Triple (KHT) on {123} in R3 at R3C4789 13a. -> {145} combo blocked for 10/3 at R3C789 (step 8) 13b. -> no 4 in R3C89 14. 15/3 at R2C6 cannot be {456} due to R3C7 14a. cannot reach cage sum with 2 of {123} 14b. -> must contain exactly 1 of {123}, which must go in R3C7 14c. -> no 1,2,3 in R2C6 15. I/O difference R12: R3C25 = R2C6 + 9 15a. -> no 9 in R3C2, no 4 in R3C5 15b. Cleanup: no 8 in R2C45 16. 9 in R3 locked in N2 -> not elsewhere in N2 17. 9 in R1 locked in N3 -> not elsewhere in N3 17a. Cleanup: no 4,5 in R1C7 18. 9 no longer available to 23/4 at R1C3 18a. -> 23/4 = {2678/3578/4568} (no 1) 18b. 8 locked for R1 19. 8 in N3 locked in R2 -> not elsewhere in R2 19a. Cleanup: no 5 in R3C2, no 4 in R3C6 (otherwise 15/3 cage sum unreachable) 20. 4 in R3 locked in N1 -> not elsewhere in N1 Now for a couple of chains (no eliminations yet): 21. if R3C7 = 2, then... 21a. -> R7C3 = 2 (step 9) 21b. -> 9/3 at R3C3 = {135} 21c. -> R3C89 <> {5..} 22. if R3C7 = 3, then... 22a. -> R3C6 <> 9 (combinations 15/3) 22b. -> R3C5 = 9 (strong link R3) 22c. -> R2C45 = {13} 22d. -> R3C4 = 2 22e. -> R3C89 <> {2..} 23. Above 2 chains (steps 21 and 22) together block {235} combo in R3C789 (step 8) 23a. -> R3C789 = {127/136} (no 5) (see also step 13a) 23b. 1 locked for R3 and N3 24. 1 in R1 locked in R1C12 24a. -> no 1 in R2C1 25. 1 in R2 locked in 13/3 at R2C4 = {139/148/157} (no 2,6) 26. {28} in R2 locked in R1 outies at R2C1789 = 19/4 = {2458/2368} (no 7) 26a. {23} only in R2C19 26b. -> no 6 in R2C9 27. {79} in 21/3 at R1C7 now only in R1C7 27a. -> {579} combo blocked 27b. -> 21/3 at R1C7 = {489/678} (no 5) 27c. 7 only in R1C7 27d. -> no 6 in R1C7 28. 5 in N3 locked in 14/3 at R1C8 = {257/356} (no 4,8,9) 29. Hidden single (HS) in R1/N3 at R1C7 = 9 29a. -> R2C78 = {48} (no 6), 4 locked for R2 29b. -> R2C19 = [25] (step 26) 29c. Cleanup: no 7,8 in R3C5 (see step 25); no 4,6 in R7C8; no 8 in R3C2; no 9 in R3C6 30. HS in R3/N2 at R3C5 = 9 30a. -> R2C45 = {13} (no 7), 3 locked for N2 31. Naked single (NS) at R3C4 = 2 31a. Cleanup: no 5 in R3C3; no 6,7 in R3C6; no 8 in R4C9 (step 10) 32. 2 in R1/N3 locked in split 9/2 at R1C89 = {27} (no 3,6) 32a. 7 locked for R1 and N3 33. HS in N2 at R2C6 = 7 33a. -> R3C67 = [53] 33b. -> R4C9 = 9 (step 10, but also obtainable via cage-split of 16/3) 33c. Cleanup: no 2,4 in R69C7 34. HS in R1/N1 at R1C3 = 5 35. HS in R3/N1 at R3C1 = 8 36. HS in R3/N1 at R3C3 = 4 36a. -> R4C3 = 3 37. HS in R3/N1 at R3C2 = 7 38. HS in C6 at R5C6 = 9 38a. Cleanup: no 4,8 in R56C5 39. Outie N47: R9C4 = 5 39a. -> no 8,9 in R89C3 40. Innie N7: R7C3 = 1 40a. -> R6C23 = [97] 41. R2C23 = [69] 42. HS in C3 at R5C3 = 8 42a. -> R45C2 = {12}, locked for C2 and N4 43. R1C12 = [13] 44. Naked triple (NT) on {456} in C1 at R456C1 -> no 4,5,6 elsewhere in C1 45. 20/3 at R8C4 = {389/479} 45a. 9 only in R8C4 45b. -> R8C4 = 9 45c. no 6 in R89C5 46. 20/3 at R8C1 = {389/479} 46a. 9 only in R9C1 46b. -> R9C1 = 9 47. HS in C8 at R7C8 = 9 47a. -> R2C8 = 4 (step 11) 47a. -> R2C7 = 8 48. Outie C45: R1C6 = 4 49. HS in C6 at R4C6 = 8 49a. -> no 6,7 in R45C7 50. Outies C6: R69C7 = 8/2 = [17] 50a. -> R67C6 = {36}; R89C6 = {12}, 2 locked for N8 50b. Cleanup: no 4 in R8C5 51. Innie N9: R7C9 = 2 51a. -> R6C89 = {68}, 6 locked for R6 and N6 (Pending naked/hidden singles now...) 52. 15/3 at R6C4 = {348} (no 6,7) 52a. 8 locked in R7C45 for R7 and N8 Now all naked singles to end._________________Cheers, MikeLast edited by mhparker on Wed Aug 08, 2007 10:38 pm; edited 1 time in total
rcbroughton
Expert

Joined: 15 Nov 2006
Posts: 143
Location: London

Posted: Sat Jul 21, 2007 11:44 pm    Post subject:

 mhparker wrote: Now for the A60RP, if Richard hasn't finished it already...
I wish! Thought I'd almost finished it and then ran into a problem because I'd made a silly mistake early on. I'm currently staring at some big contradiction moves to get through it - there must be a better way?

Anybody want to play tag?

Rgds
Richard
herschko
Rookie

Joined: 22 Jun 2007
Posts: 6
Location: Highland Park, NJ

 Posted: Sat Jul 21, 2007 11:58 pm    Post subject: I got this one done on Friday. Interesting one. I used some algebra to get nonobvious relations between remote cells. (Is that remark a spoiler? Sorry if so.) I confess I had to guess twice. The relation I speak of is A7 + G3 = 4, where letter indicates column. The guesses: 2 in each of these cells leads to a contradiction. Then I tried 1 and 3 for A7. _________________-SJH
mhparker
Grandmaster

Joined: 20 Jan 2007
Posts: 345
Location: Germany

Posted: Mon Jul 23, 2007 12:52 pm    Post subject:

Hi folks,

 Ruud (on the 'Assassin 60 - the Rejected Pattern' thread) wrote: Here is a cage pattern that I tried over and over again, but failed to create a suitable Assassin.

Well, being concerned that the "24-carat piece" created by Ruud may prove to be impregnable, I set about continuing the search for an alternative based on the same rejected pattern (RP). After several hours' intensive work, I came up with this. It waits for your approval...

Assassin 60 RP-Lite

3x3::k:2560:2560:3330:3330:3330:4869:4869:6151:6151:2560:4874:4874:3084:3084:2574:4869:4869:6151:2322:4874:5908:5908:3084:2574:2574:3353:6151:2322:4124:5908:4894:4894:5152:5152:3353:3353:2322:4124:4124:4894:3880:3880:5152:5419:3353:5677:4654:4654:2608:3880:2866:2866:5419:5419:5677:5677:4654:2608:2608:2866:4412:4412:5419:5951:5677:4161:4161:6467:6467:4412:5190:5190:5951:5951:5951:4161:4161:6467:6467:5190:5190:

P.S. Don't be put off by the word "Lite" in the name - it ain't that easy!
_________________
Cheers,
Mike
Para
Yokozuna

Joined: 08 Nov 2006
Posts: 384
Location: The Netherlands

 Posted: Mon Jul 23, 2007 4:37 pm    Post subject: Hi all Finally finished it. Had to write my whole walk-through over because word crashed on me before i saved anything. So it works a bit backwards. It opens with the moves that finally broke it open for me(because they were there from the beginning), and ends with the easier bits. Walk-through Assassin 60 1. 6(3) at R1C1 = {123} -->> locked for N1 2. 21(3) at R1C7 = {489/579/678}: no 1,2,3 3. 22(3) at R2C2 = {589/679}: no 4; 9 locked for N1 4. 9(3) at R3C3 = {126/135/234}: no 7,8,9 4a. Needs one of {456}, goes in R3C3: R3C4 + R4C3: no 4,5,6 5. 11(3) at R4C2 = {128/137/146/236/245}: no 9 6. 10(3) at R6C6 and R8C6 = {127/136/145/235}: no 8,9 7. 20(3) at R7C7, R8C1 and R8C4 = {389/479/569/578}: no 1,2 8. 45 on N124: 2 outies: R3C7 + R7C3 = 4 = {13/22}: no 4,5,6,7,8,9 9. 45 on N3: 3 innies: R3C789 = 10 = {127/136/145/235}: no 8,9 9a. 45 on N3: 1 innie and 1 outie: R4C9 = R3C7 + 6 -->> R4C9 = {789} 10. 45 on R12: 4 outies: R3C2567 = 24 = {1689/2589/2679/3489/3579} = {7/8}({3678} blocked: 9 locked in these R3C256 for R3): Needs on of {123} in R3C7 -->> R3C56: no 1,2,3 10a. R3C7 + R7C3 = {22} -->> R3C4 + R4C3 = {13} -->> R3C3 = 5: R3C2567: {2589} blocked. 11. R3C789: no {127}: no 7 11a. Explanation: R3C789 = [1]{27} clashes with 16(3) cage at R3C8 11b. R3C789 = [2]{17}: blocked by R3C2567: when R3C7 = 2, R3C256 = {679} 12. Hidden Killer Pair {78} in R3C1 + R3C2567 for R3(R3C2567 needs one of {78} and only other place for {78} in R3 is R3C1) -->> R3C1 = {78} 13. 45 on N1: 3 innies: R1C3 + R3C13 = 17 = {458/467} -->> R13C3 = {45/46}: no 7,8; 4 locked for C3 14. 45 on N7: 3 innies: R789C3 = 9 = {126/135/234}: no 7,8,9 14a. 45 on N7: 1 innie and 1 outie: R9C4 = R7C3 + 4 -->> R9C4 = {567} 15. 13(3) at R8C3 = {157/256}(only remaining combinations) = {15}[7]/{25}[6]/{26}[5] -->> R89C3 = {15/25/16}: no 3 16. Killer Pair {56} in R13C3 + R89C3 locked for C3 17. 45 on C12: 4 outies : R2567C3 = 25 = {1789} -->> R7C3 = 1, R256C3 = {789} 17a. R9C4 = 5(step 14a); R3C7 = 3(step 8); R4C9 = 9(step 9a), R4C3 = 3(hidden) 17b. R89C3 = {26} -->> locked for C3 and N7 18. 11(3) at R4C2 = {128} (only possible combination as it needs one of {78} in R5C3) -->> R5C3 = 8; R45C2 = {12} -->> locked for C2 and N4 18a. R1C2 = 3 19. 23(4) at R3C1 = {4568} (last possible combination): no 7,9; R3C1 = 8; R456C1 = {456} -->> locked for C1 and N4 19a. R6C23 = {79} -->> locked for R6 19b. R789C1 = {379} -->> locked for N7 19c. R789C2 = {458} -->> locked for C2 20. R3C2567 = 3{579}: R3C256 = {579} -->> locked for R3 20a. R3C3 = 4; R3C4 = 2; R1C3 = 5; R2C2 = 6(hidden) 21. 6 in N2 locked in R1C456 -->> 23(4) at R1C3 = 5{468} -->> R1C456 = {468} -->> locked for R1 and N2 21aa. R3C89 = {16} -->> locked for N3 (did this but not on paper) 21a. R1C1 = 1(hidden); R2C1 = 2 21b. R1C789 = {279} -->> locked for N3 22. 15(3) at R2C6 = 3{57}(last remaining combination) -->> R23C6 = {57} -->> locked for C6 and N2 22a. R3C5 = 9; R3C2 = 7; R2C3 = 9; R23C6 = [75]; R6C23 = [97]; R5C6 = 9(hidden) 23. 21(3) at R1C7 needs 2 of {458} in R2C78 -->> 21(3) = {489} -->> R1C7 = 9; R2C78 = {48} -->> locked for N3 23a. R2C9 = 5 24. 20(3) at R8C4 = {389/479} -->> R8C4 = 9; R89C5 = {3478} 25. 20(3) at R8C1 = {389/479} -->> R9C1 = 9 25a. R7C8 = 9(hidden) 26. 45 on C89: 1 innie: R2C8 = 4; R2C7 = 8 27. 1 in N8 locked for C6 and 10(3) cage at R8C6 27a. 10(3) at R8C6 = {127/136} -->> R89C6 = {12/13}: no 4,6; R9C7 = {67} 28. 45 on N69: 1 outie and 2 innies: R4C6 = R69C7: Min R69C7 = 7 -->> R4C6 = 8 -->> R69C7 = [17/26]: R6C7 = {12} 29. 10(3) at R6C6 = {136}: no {24} 29a. R6C7 = 1; R9C7 = 7; R1C6 = 4(hidden) 30. 45 on N9: 1 innie: R7C9 = 2 30a. R1C89 = [27]; R6C5 = 2(hidden); R5C5 = 6; R67C6 = [36] 30b. R6C4 = 4; R1C45 = [68]; R4C5 = 5(hidden) 31. 45 on R6789: 1 innie: R6C1 = 5 31a. R45C1 = [64] And the rest is all singles greetings ParaLast edited by Para on Thu Aug 02, 2007 7:35 pm; edited 2 times in total
mhparker
Grandmaster

Joined: 20 Jan 2007
Posts: 345
Location: Germany

Posted: Tue Jul 24, 2007 8:46 am    Post subject:

Hi Richard,

Congratulations on your 100th post!

rcbroughton wrote:
 mhparker wrote: Now for the A60RP, if Richard hasn't finished it already...
I wish! ... I'm currently staring at some big contradiction moves to get through it - there must be a better way?

I'm not sure. After doing some initial pre-analysis of this puzzle, I thought to myself: "I'm not getting into the [boxing] ring with that one!". I had the same sinking feeling with the A50V2, which apparantly no one else (apart from Glyn) wanted to touch either! A bit like trying to break into Fort Knox armed with only a hacksaw and crow bar. In other words, sounds like the perfect "challenge" for you and Ed to me!

 rcbroughton wrote: Anybody want to play tag?

Maybe it would be a good idea to type up what you've found so far, so that others the "opportunity" to join in. Not sure you can count on me, though.

By contrast, the "Lite" version I created should be more fun! It would be very interesting to see how the other forum regulars get on with it. (In case you ask: no, I haven't done it myself yet!). Here, it may be a good idea for people to start it individually, and open it up as a team tag solution later if they get stuck.
_________________
Cheers,
Mike
CathyW
Master

Joined: 31 Jan 2007
Posts: 161
Location: Hertfordshire, UK

 Posted: Tue Jul 24, 2007 9:43 am    Post subject: Edit: Thanks to Ed and Mike - hopefully this one is error free. I think I'd previously left in an invalid step from WT1. Thankfully the end result is the same. At the third attempt: 1. 6(3) N1 = {123} not elsewhere in N1 2. 22(3) N1 = {589/679} 9 not elsewhere in N1 3. Innies N1 r1c3 + r3c13 = 17 = {458/467} -> r3c3 = (456) -> r3c4, r4c3 of 9(3) = (123) 4. Innies N3: r3c789 = 10 = {127/136/145/235} 5. Outies  Innies N3: r4c9  r3c7 = 6 -> r3c7 = (123), r4c9 = (789) -> r23c6 = (49) 6. O-I r123: r4c39  r3c1 = 4; r4c39 min 8, max 12 7. O-I N2: r1c3 + r3c7  r3c4 = 6 -> r1c3 <> 6 r1c3 + r3c7 = r3c4 + 6 = 7, 8 or 9 = [52/43], [53/71], [81/72] 8. Innies N9: r7c9 + r9c7 = 9 = [81]/{27/36/45} 9. Innies N7: r789c3 = 9 = {126/135/234} 10. O-I N7: r9c4  r7c3 = 4 r9c4 = (59) -> r7c3 <> 6 11. Innies r89: r8c27 = 11 = [29]/{38/47/56} 12. Innies r6789: r6c15 = 7 = {16/25/34} 13. Innies c89: r27c8 = 13 = {49/58/67} 14. Innies N5689: r4c9 + r9c4 = 14 = [95/86/77] -> r9c4 <> 8,9 -> r7c3 <> 4,5 -> r6c23 = (59) 15. Innies c6789: r15c6 = 13 = {49/58/67} 16. Outies N124: r3c7 + r7c3 = 4 = {13/22} 17. O-I r12: r3c25  r2c6 = 9 -> r3c25 min 13, max 17 -> r2c6 <> 9 a) r2c6 = 4 -> r3c25 = {58/67} ({49} not an option} b) r2c6 = 5 -> r3c25 = [59]/{68} c) r2c6 = 6 -> r3c25 = [69]/{78} d) r2c6 = 7 -> r3c25 = [79] e) r2c6 = 8 -> r3c25 = [89] For all options r3c2 <> 9 -> 9 locked to r2c23, not elsewhere in r2. -> r7c8 <> 4 -> 9 locked to r1c789 -> r1c456 <> 9 -> r5c6 <> 4 18. 23(4) r1c3456 = {2678/3578/4568} no 1 and must have 8 -> r1c789 <> 8 -> 8 locked to r2c789, not elsewhere in r2 -> r3c2 <> 5 19. O-I c123: r39c4  r1c3 = 2 a) r1c3 = 4 -> r39c4 = 6 = [15] b) r1c3 = 5 -> r39c4 = 7 = [16/25] c) r1c3 = 7 -> r39c4 = 9 = [27/36] d) r1c3 = 8 -> r39c4 = 10 = [37] 20. O-I N4 r3c1+r7c3-r4c3 = 6 -> r3c1 <> 6 21. From step 6: a) r3c1 = 4 -> r4c39 = 8 = [17] b) r3c1 = 5 -> r4c39 = 9 = [18/27] c) r3c1 = 7 -> r4c39 = 11 = [29/38] d) r3c1 = 8 -> r4c39 = 12 = [39] 22. 21(3) N3: If {489} r1c7 = 9 -> r1c7 <> 4; if {579} r1c7 = 9 -> r1c7 <> 5 23. 17(3) N5: r5c5 <> 1 since no 7 or 9 in r6c5 24. From step 9: split 9(3) r789c3 = {126/135/234}  must have two of 123; r4c3 = (123) Killer combination on 1, 2, 3 -> r5c3 <> 1,2,3 -> r45c2 <> 7,8 25. 15(3) r3c7+r23c6 = 1[59/68], 2[49/58]/{67}, 3[48]/{57} -> r3c6 <> 4 26. Outies N1234: r4c9+r7c3 = 10 = [73/82/91] 27. Outies N1247: r3c7+r9c4 = 8 = [17/26/35] 28. 21(3) N3 = {489/579/678} -> Combinations {158/347} blocked for 14(3) N3 -> 14(3) = {149/167/239/248/257/356} 29. 16(3) r7c12+r8c2 = {169/178/268/349/358/457} Combination {259/367} blocked by split 9(3) r789c3 30. Outies c89: r1278c7 = 28 = {4789/5689} -> r45c7 <> 8, 9 -> split 11(2) r8c27 = [29/38/47/56/65/74] (r8c2 <> 8) 31. 20(3) N9 = {479/569/578} -> split 9(2) N9 <> {45}, 16(4) N9 <> {45} but must have one of 4,5 -> 16(4) = {1249/1258/1348/2347/2356} ({1357 blocked by 20(3)) 32. O-I c12: r25c3  r6c2 = 8 -> r25c3 min 13, max 17 33. Outies r12: r3c2567 = 24 (9 locked to r3c56) = [6{89}1]/[6{79}2]/[7{69}2]/[7953]/[8{69}1]/[8{59}2] ([7593] not possible as couldnt make up 15(3) r23c6+r3c7) 34. Innies N5: r4c6+r6c46 = 15 35. Outies c12: r2567c3 = 25 = {1789/2689/3589/3679} (4 eliminated from r5c3) -> r45c2 of 11(3) <> 5,6 -> 11(3) N4 = {128/137/146/236/245} 36. 23(4) r1c3456 = {2678/3578/4568}  Must have one of 3,6 within N2 -> 13(3) N2 <> {346} 37. From step 16: a) r3c7 = 1, r7c3 = 3 -> r4c9 = 7, r9c4 = 7 NT {689} r3c256 (step 33) -> r3c89 = {45} CONFLICT  no candidates would be left in r3c3 -> r3c7 <> 1, r7c3 <> 3 -> r9c4 <> 7 -> r4c9 <> 7 b) r3c7 = 2, r7c3 = 2 -> r4c9 = 8, r9c4 = 6, r3c4+r4c3 = {13} -> r3c3 = 5 -> 22(3) N1 = {679}  OK c) r3c7 = 3, r7c3 = 1 -> r4c9 = 9, r9c4 = 5, -> r3c256 = [795] -> r23c6 = [75] -> r2c23 = {69} Conclusion: either remaining option for split 4(2) r3c7 + r7c3, 22(3) N1 = {679} -> split 17(3) N1 = {458} 38. 9(3) r3c34+r4c3 = 4{23}/5{13} -> either r3c4 or r4c3 = 3 -> r4c4 <> 3 39. From step 17: a) r2c6 = 4 -> r3c25 = {67} b) r2c6 = 5 -> r3c25 = [68] c) r2c6 = 6 -> r3c25 = [78] d) r2c6 = 7 -> r3c25 = [79] -> r3c5 <> 5 -> r2c45 <> 7 -> split 24(4) r3c2567 = [6{79}2]/[7{69}2]/[[7953] -> r3c56 <> 8 -> HS r3c1 = 8 (Andrew pointed out: Step 39d also gives r2c6 <> 5,6 since 39b and 39c no longer apply.) 40. NP {45} r13c3 -> 4,5 not elsewhere in c3 -> 13(3) r89c3+r9c4 = {26}5 -> r4c9 = 9, r3c7 = 3, r7c3 = 1 -> 2,6 not elsewhere in N7/c3 -> r4c3 = 3, r6c23 = {79} not elsewhere in N4/r6 -> r5c3 = 8, r45c2 = {12} -> r1c2 = 3 -> r12c1 = {12}, r456c1 = {456}, r789c1 = {379}, r789c2 = {458} 41. UR r2c2 = 6 -> r3c2 = 7, r2c3 = 9, r6c2 = 9, r6c3 = 7,  (Andrew commented: It looks as if theres also UR r3c2 = 6 -> r2c23 = {79}, r6c23 = {79} -> r3c2 = 7.) Relatively straightforward cage combos and singles from here 1 3 5 6 8 4 9 2 7 2 6 9 3 1 7 8 4 5 8 7 4 2 9 5 3 1 6 6 2 3 1 5 8 4 7 9 4 1 8 7 6 9 2 5 3 5 9 7 4 2 3 1 6 8 7 4 1 8 3 6 5 9 2 3 5 2 9 7 1 6 8 4 9 8 6 5 4 2 7 3 1 PS I've finished 'pottering' as well! Did someone mention work?!Last edited by CathyW on Thu Aug 16, 2007 3:52 pm; edited 4 times in total
Para
Yokozuna

Joined: 08 Nov 2006
Posts: 384
Location: The Netherlands

Posted: Tue Jul 24, 2007 10:41 am    Post subject:

 CathyW wrote: PS I've finished 'pottering' as well! Did someone mention work?!

I think that was only you.
Para
Yokozuna

Joined: 08 Nov 2006
Posts: 384
Location: The Netherlands

 Posted: Wed Jul 25, 2007 12:36 am    Post subject: How are the rest of you doing on Mike's RP-Lite? Been hacking away at it for a while. Now have 2 placements but still it won't crumble. Hope it falls tomorrow. Good night Para
Andrew
Grandmaster

Joined: 11 Aug 2006
Posts: 300
Location: Lethbridge, Alberta

Posted: Wed Jul 25, 2007 5:15 am    Post subject:

 CathyW wrote: PS I've finished 'pottering' as well!

Was that the 7th book, the 5th film or both?

We went to see the film at the weekend, another reason why I still haven't started Assassin 60.

Our younger daughter has the book on order from Amazon but they didn't offer first day delivery in Lethbridge. No problem since she has just started re-reading the first six books. Maybe I'll get to read the new one later this year after our daughters and my wife have both read it.
CathyW
Master

Joined: 31 Jan 2007
Posts: 161
Location: Hertfordshire, UK

 Posted: Wed Jul 25, 2007 7:46 am    Post subject: The 7th book. And no I'm not going to give anything away!! The 5th film we will be going to see but probably not until after our holiday (5th-12th August in Chamonix, France) so I'll have to hope the A62 can be solved before I go and catch up with the A63 when I get back.
mhparker
Grandmaster

Joined: 20 Jan 2007
Posts: 345
Location: Germany

Posted: Wed Jul 25, 2007 7:53 am    Post subject:

 Andrew wrote: Maybe I'll get to read the new one later this year after our daughters and my wife have both read it.

Talking about books, have you read Andrew Stuart's "The Logic of Sudoku" yet, or is it still sitting on the shelf in pristine condition?

My copy is falling apart at the seams and is rapidly becoming a collection of individual pages!
_________________
Cheers,
Mike
CathyW
Master

Joined: 31 Jan 2007
Posts: 161
Location: Hertfordshire, UK

 Posted: Wed Jul 25, 2007 1:17 pm    Post subject: A60RP Lite Edit: It's no good. I'm not getting any further. Very frustrating having reached a solution with a mistake so I know what the answer is but I can't find a way to prove it! Going to try and follow Para's WT now. (Taken out of tiny text since A61 will be out tomorrow!) 1. Innies N1: r1c3+r3c13 = 16 2. Innies N5: r4c6+r6c46 = 11 (no 9) Since r4c6 is min 3, r6c46 is max 7 -> r4c6 = (38), r6c46 = (17) 3. Innies N9: r7c9+r9c7 = 8 = {17/26/35} 4. Innies c89: r27c8 = 12 = {39/48/57} 5. Innies r89: r8c27 = 6 = {15/24} 6. Outies - Innies r6789: r5c8 - r6c5 = 3 -> r5c8 = (49), r6c5 = (16) 7. Innies r123: r3c1348 = 28 = {4789/5689} -> r3c34 = {89} -> r4c3 = 6 -> r3c1 = (456), r3c8 = (567), r1c3 = (123) -> split 16(3) N1 now [169/259/268/358/349] -> 9(3) r345c1 = 4{23}/5{13}/6{12} -> r45c1 <> 4,5 8. O-I N4: r3c1+r7c3 - r6c1 = 4 -> r7c3 <> 4 9. O-I N7: r78c3 = r6c1 -> r78c3 <> 9, r6c1 <> 1,2 10. Using steps 8 and 9 together (ie. O-I N47): r3c1 + r7c3 = r6c1 + 4 r8c3 + r7c3 = r6c1 r3c1 - r8c3 = 4 -> r3c1 = (56), r8c3 = (12) -> split 28(4) r3 = {5689} not elsewhere in r3 -> r8c3 forms killer pair with split 6(2) r8c27 -> 1,2 not elsewhere in r8 11. 13(4) r3c8+r4c89+r5c9 = 5{134}/6{124} -> 1,4 not elsewhere in N6 -> from step 6: r6c5 <> 1 12. O-I c123: r3c4 - r18c3 = 5 a) r3c4 = 8 -> r18c3 = {12} b) r3c4 = 9 -> r18c3 = [31] -> 1 not elsewhere in c3 13. 9(3) r345c1 = 5{13}/6{12} -> 1 not elsewhere in c1 14. O-I c6789: r8c5 = r5c6 (39) 15. Outies r6789: r5c568 = 18 16. Split 16(3) N1 now [169/259/268/358] Must have at least one of 89 -> 19(3) N1 <> {289} -> 19(3) N1 = {379/469/478} -> r2c23 <> 5 17. 1 locked to r1c23 not elsewhere in r1 18. 10(3) N1 = {127/136/145/235} Analysis: r1c2 <> 4,6,7 19. 1 locked to r4c46 -> r5c5 <> 1 -> split 11(3) N5 = 1{28/37/46} (no 5) -> r6c46 <> 4 20. Outies N5689: r3c8 + r8c3 = 7 = [52/61] 21. Pointing cells: 8,9 locked to r6789c1 -> r7c2 <> 8,9 22. From step 9: r6c1 = r78c3 Options: [3/21], [4/31], [5/32], [7/52], [8/71], [9/81] 23. O-I r12: r3c259 - r2c6 = 7 a) r2c6 = 1 -> r3c259 = {34}1, r3c67 = {27} OK b) r2c6 = 2 -> r3c259 = {34}2, r3c67 = {17} OK c) r2c6 = 3 -> r3c259 = 7{12}, r3c67 no options d) r2c6 = 4 -> r3c259 = {137}, r3c67 no options e) r2c6 = 5 -> r3c259 = {147/237}, r3c67 = {14/23} f) r2c6 = 6 -> r3c259 = {247}, r3c67 = {13} g) r2c6 = 7 -> r3c259 = {347}. r3c67 = {12} -> r2c6 <> 3,4 24. 18(3) r6c23+ r7c3 = {279/378/459} If {459} r7c3 = 5 -> r6c23 <> 5 25. 17(3) N9 = {179/269/278/359/458/467} If {179} r8c7 = 1 -> r7c7 <> 1 If {269/278} r8c7 = 2 -> r7c7 <> 2 26. 20(3) r4c67+r5c7 = {389/479/578} {569} not possible -> r5c7 <> 6 27. 19(3) N5 = {289/379/469/478/568} -> r4c5 <> 2 (cant have both {89} in r45c4 because r3c4 = (89)) -> if {568} r5c4 = 6 -> r5c4 <> 5 28. 11(3) r6c67 + r7c6 = {128/137/146/236}/[254] -> r7c6 <> 5 29. O-I N3: r3c78 - r1c6 = 2 (r3c78 = r1c6 +2) r3c78 min 6 -> r1c6 min 4 r3c78 max 11 -> r3c7 <> 7 Max available from r3c78 is 10 -> r1c6 <> 9 30. 24(4) N3 = {1689/2589/2679/3489/3579/3678/4578} ({4569} blocked by r3c8) If {1689}, r3c9 = 1 -> r2c9 <> 1 If {2589/2679}, r3c9 = 2 -> r2c9 <> 2 31. Innies c123: r138c3 = 12 = [192/291/381] 32. Outies c6789: r568c5 = 15 33. 19(3) N1 <> {379} else no options for split 12(3) in c3 -> 19(3) = {478}/[694] -> 4 not elsewhere in N1 -> 9 locked to r23c3, not elsewhere in c3 -> r6c2 <> 2,4 (cant make 14 or 16 with remaining candidates in r67c3) -> 18(3) r6c23+r7c3 = {378}/9{27}/[945] 34. 10(3) N1 = {127/136/235} must have at least one of 2,3 in r12c1 9(3) r345c1 must have at least one of 2,3 in r45c1 -> KP: 2,3 not elsewhere in c1 35. Split 16(3) N1 = {169/259/358} {268} now blocked by options for 19(3) N1 36. 9(3) r345c1 a) if 6{12} -> 10(3)N1 = {235} b) if 5{13} -> 10(3)N1 = {127} -> r12c1 <> 6 37. 10(3) N1 must have 2 -> r3c1 <> 2 -> split 16(3) N1 = [169/358] -> split 12(3) c3 = [192/381] 38. 25(4) r8c56+r9c67 = {1789/2689/3589/3679/4579/4678} (Must have at least one of 4 and 9). -> 16(4) r8c34+r9c45 can't have both 49 -> {1249} blocked. -> 16(4) = {1258/1267/1348/1357/1456/2347/2356} (no 9) -> 9 locked to r8c56+r9c6 of 25(4) -> option {4678} no longer possible 39. Pointing cells: 4 locked to r6789c1 -> r78c2 <> 4 -> r8c7 <> 2 -> 2 locked to r8c23, not elsewhere in N7 40. 17(3) N9 = {179/359/458/467} Must have one of 4, 9 -> 20(4) N9 can't have both 4,9 but must also have one. 20(4) options: {1289/1379/1478/2369/2468/3458/3467} 41. 23(4) N7 = {1589/1679/3479/3569/3578/4568} Can't have both {56} in r89c1 because r3c1 = (56) 42. Innies c6789: r589c6+r9c7 = 25 9 locked to r589c6 -> 25(4) = {1789/2689/3589/3679/4579/} Can't have repeated candidates in this complex cage because r5c6 = r8c5 (step 13) 43. Split 6(2) r8c27 = {15}/[24] a) if {15} -> 5 not elsewhere in r8, r8c3 = 2 -> r3c1 = 6 b) if [24] -> r8c3 = 1, r3c1 = 5 Either case r8c1 <> 5 44. 10(3) N1 = {27}1/{235} a) r1c2 = 1 -> r12c1 = {27} -> 9(3) c1 = 5{13} OK b) r1c2 = 2 -> r12c1 = {35} -> 9(3) c1 = 6{12} OK c) r1c2 = 3 -> r12c1 = {25} -> 9(3) c1 no options d) r1c2 = 5 -> r12c1 = {23} -> 9(3) c1 no options -> r1c2 <> 3,5 -> 5 locked to r123c1, not elsewhere in c1 -> 5 locked to 16(3) in N4 = 5{29/38/47} ... Last edited by CathyW on Thu Jul 26, 2007 4:24 pm; edited 4 times in total
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