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Assassin 79

 
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sublue
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Joined: 12 Oct 2007
Posts: 21
Location: Champaign, Illinois, USA

PostPosted: Fri Nov 30, 2007 4:06 am    Post subject: Assassin 79 Reply with quote

I get to be first, with no miracle guesses this time!
Thanks to Afmob and Andrew for correcting typos!
Prelims:
a) N1: Two 13(2) no 1,2,3
b) N12: 6(3) no 4,5,6,7,8,9
c) N12: 14(2) no 1,2,3,4,7
d) N14: 14(4) no 9
e) N3: 8(3) no 6,7,8,9
f) N47: 20(3) no 1,2
g) N5: 32(5) no 1
h) N45 and N56: 6(2) no 3,6,7,8,9
i) N58: 7(3) no 3,5,6,7,8,9
j) N6: 19(3) no 1
k) N78: 29(4) no 1,2,3,4,6
l) N89: 15(2) no 1,2,3,4,5
m) N9: 7(2) no 7,8,9
n) N9: 8(2) no 4,8,9

Solving:
1) R1C234 6(3) = {123} locked for R1

2) N3: 8(3) 1 locked for N3.

3) R5: locked quad {1245} in the two 6(2) for R5.

4) R12: 2 innies R2C28 = 8 -> R2C2 = {567}, R2C8 = {123}
a) R3C2 = {678}

5) R89: 2 innies R8C28 = 5 -> R8C28 = {1234}
a) R7C8 = {3456}

6) N5: 4 innies R45C6 + R56C4 = 13.
a) R4C6 = {36} -> r3c56 NO 3,6,9
b) 1,4 locked into R5C46 and R6C4 for N5

7) N78: 29(4) {5789} locked
a) R8C56 no 5,7,8,9

8) C1: 4 innies: R3489C1 = 12 -> R3489C1 no 7,8,9

9) N3: 2 innies: R2C7+ R3C9 = 12 - > R2C7 and R3C9 no 2,6

10) N7: 2 innies R7C1 + R8C3 = 17 -> R7C1 and R8C3 = {89} locked for N7
a) Cleanup: R7C6 no 7 -> R7C7 no 8 because of the 29(4). R9C6 no 5,7.

11) R789: 2 innies and 1 outie R7C19 = R6C4 + 9 -> R7C9 = {12345}

12) 9 locked in N4 R56C2 n/e.

13) N47: 2 innies and 1 outie: R58C3 = R3C1 +10 -> R5C3 no 1 -> R5C4 no 5, R3C1 no 5,6

14) R567C4 = {124} triple locked for C4
a) Cleanup: R1C4 = 3
b) R1C23 no 3 -> {12} locked for N1

15) N1: 3 innies R23C3 + R3C1 = 16 -> R2C3 no 6,9

16) N12: 13(3) R2C3 no 8, R2C5 no 5,6,7,8,9

17) N89: 17(3) r8C7 = {789} R8C56 no 1,2. 6 locked into R8C56 for N8, R8. R8C7 no 9
a) Cleanup: R9C9 no 2, R7C7 no 9.

18) N8: Quad {5789} at R7C6 and R8C4 and R9C45 -> no 8,9 at R9C6

19) N89: 15(3) R9C78 no 1. 9 locked into R9C78 -> R9C78 no 3,6,7,8

20) N9: R8C7 = 8 since n/e.
a) Cleanup: R8C3 = 9
b) R7C1 = 8
c) R3C4 no 5
d) R12C1 no 5
e) R7C6 = 9
f) R56C1 = [75]
g) R12C1 = {49} locked for C1
h) R5C34 = {24} locked for R5
i) Remainder of puzzle continues to be cleanup, simple sums, hidden and naked singles.

421395768
965718324
378642159
182956473
794231586
536487912
847129635
219563847
653874291


Editted twice for typos.
_________________
Susan


Last edited by sublue on Mon Dec 03, 2007 2:09 pm; edited 2 times in total
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Afmob
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Joined: 22 Sep 2007
Posts: 103
Location: MV, Germany

PostPosted: Fri Nov 30, 2007 4:47 pm    Post subject: Reply with quote

This one was special since it led to my shortest walkthrough I've written so far. Normally I need some hours to solve Ruud's Assassins but this time it took me about 40 minutes, but more like 2 hours Laughing since I've made mistakes somewhere and had to start over again twice.

Edit: Made a mistake in the beginning which led to a quicker solution. Thanks to Andrew, I corrected it. So after rewriting my walkthrough I still managed to make it my shortest one so far, but it's a bit longer than my first path.

Let's see how demanding the RP version is.

A79 Walkthrough:

1. R789
a) Innies R89 = 5(2) = {14/23}
b) 29(4) = {5789} locked between R8+N8 -> R8C56 <> 5,7,8,9
c) 17(3): R8C7 = (789) because R8C56 <= 10
d) 6 locked in 17(3) = 6{29/38/47} for R8+N8 because (789) only possible @ R8C7
e) 7(2): R7C8 <> 1,2
f) 8(2): R9C9 <> 2
g) Innies N7 = 17(2) = {89} locked for N7
h) 29(4) = {5789} -> 5,7 locked for N8
i) Naked pair (89) locked in R7C16 for R7

2. R789 !
a) ! 15(3) must have 8 xor 9 because it's only possible there and @ R8C7 for N3
-> R8C7 = (89)
b) 17(3) = 6{29/38}
c) Killer pair (23) of 17(3) blocks {23} of Innies R89 = 5(2)
d) Innies R89 = 5(2) = {14} locked for R8
e) 7(2) = [34/61]
f) 8(2): R9C9 <> 7
g) Innies N9 = 30(5) = 89{157/247/256}, {34689} blocked by Killer pair (36) of 7(2)
h) Innies N9 must have 6 xor 7 and R7C7 = (67) -> R7C9+R9C78 <> 6,7

3. R123
a) Innies N3 = 12(2) <> 1,2,6
b) 6 locked in 25(4) @ N3 = 6{289/379/478}
c) Innies R12 = 8(2) = [53/62/71]
d) 13(2): R3C2 <> 4,5,9

4. N4
a) Outies N4 = 13(2+1): R3C1+R5C4 <> 5,6,7,8,9 because R7C1 >= 8
b) 6(2) @ N4: R5C3 <> 1

5. C1234
a) Naked triple (124) locked in R567C4 for C4
b) 6(3) = {123} -> R1C4 = 3, {12} locked for N1+R1
c) Outies N4 = 13(2+1): R5C4 <> 4 because R37C1 >= 11
d) 6(2) = [42/51]
e) 9 locked in R56C2 for N4
f) 18(3) = 9{18/27/36} because {459} blocked by R5C3 = (45)

6. N36
a) Outies N6 = 15(2+1): R3C9 <> 3,4,5 because R5C6+R7C9 <= 10 and {55}+5 impossible
b) Innies N3 = 12(2) = [39/48/57]

7. R456 !
a) ! Innies+Outies R123: -6 = R4C6 - R3C19
-> R4C6 <> 1,2,3 because R3C19 >= 10
b) 3 locked in 32(5) = {35789} locked for N5
c) Hidden Single: R4C6 = 6 @ N5, R8C5 = 6 @ N8
d) 12(3) = 6{15/24}

8. R123 !
a) ! Killer pair (45) locked in 12(3)+8(3) for R3
b) 14(2) = {68} locked for R3
c) R3C2 = 7 -> R2C2 = 6, R3C3 = 8
d) 13(2) = {49} locked for C1+N1
e) Innies N3 = 12(2) = [39] -> R3C9 = 9, R2C7 = 3
f) 25(4) @ N2 = {3589}, {589} locked for N2

9. N45
a) 20(3) = {578} -> R7C1 = 8, {57} locked for C1+N4
b) R5C3 = 4 -> R5C4 = 2
c) R5C6 = 1 -> R5C7 = 5

10. N69
a) Outies N6 = 15(2+1) -> R7C9 = 5
b) R7C6 = 9 -> R7C7 = 6
c) 8(2) = {17} -> R9C9 = 1, R8C9 = 7
d) 18(3) = {369} -> R4C9 = 3, R5C9 = 6

11. Rest is singles.

Rating: 1.0


Last edited by Afmob on Thu Dec 06, 2007 9:47 pm; edited 2 times in total
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CathyW
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Joined: 31 Jan 2007
Posts: 161
Location: Hertfordshire, UK

PostPosted: Fri Nov 30, 2007 5:37 pm    Post subject: Reply with quote

Very Happy Brain is back in gear!

No WT but a key move was outies - innies of N12. First placement was r1c4 = 3.
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gary w
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Joined: 07 Sep 2007
Posts: 84
Location: south wales

PostPosted: Sat Dec 01, 2007 12:06 am    Post subject: 79 Reply with quote

A nice one..no severe combo crunching needed.And a neat start possible...



1.O-I N1245 -> R2C7+R7C1=R5C6+R6C4+6 and r7c1=8/9
2.I N5 =13/4 and this,together with constraints from the two 6(2) cages means that r5c6+r6c4=6 max (other combos impossible)
3.r2c7+8/9=12 max thus r2c7=3/4 (innies N3=12/2) r3c9=8/9
4.O-I N123 r3c19=r4c6+6
5.O-I N12 r3c1+6=r2c7+r4c6
6.Now only options for r4c6=3/6
6a if 3 -> r2c7=4 r3c1=1 and r3c9=8
6b now cannot complete 14(2) cage N12 and 8(3) cage N3
7.Thus r4c6=6
8.Thus r2c7=r3c1 (5. above) and also =r1c4
8a thus all these must=3 and r3c9=9
9. I r12 r2c28=8 -> 13(2) cage r23c2={67}
9a thus r3c4=6 r3c3=8 r8c3=9 r1c7=8

Mop up now



Regards

Gary
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Andrew
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Joined: 11 Aug 2006
Posts: 300
Location: Lethbridge, Alberta

PostPosted: Mon Dec 03, 2007 6:27 am    Post subject: Reply with quote

My solution seems to have taken a bit longer than some of the others. I missed a few things and was slow to spot others that I ought to have seen earlier, in particular I ought to have seen step 23, my breakthrough move, earlier.

I'll rate it as a moderate to harder 1.0.

Here is my A79 walkthrough.

Prelims

a) R12C1 = {49/58/67}, no 1,2,3
b) R23C2 = {49/58/67}, no 1,2,3
c) R3C34 = {59/68}
d) R5C34 = {15/24}
e) R5C67 = {15/24}
f) R7C67 = {69/78}
g) R78C8 = {16/25/34}, no 7,8,9
h) R89C9 = {17/26/35}, no 4,8,9
i) R1C234 = {123}, locked for R1
j) 8(3) cage in N3 = 1{25/34}, 1 locked for N3
k) 19(3) cage in N6 = {289/379/469/478/568}, no 1
l) R567C1 = {389/479/569/578}, no 1,2
m) 7(3) cage at R6C4 = {124}, CPE no 1 in R89C4
n) 14(4) cage at R3C1 = {1238/1247/1256/1346/2345}, no 9
o) 29(4) cage at R8C3 = {5789}, CPE no 5,7,8,9 in R8C56
p) 32(5) cage in N5 = {26789/35789/45689}, no 1, 8,9 locked for N5

1. Naked quad {1245} in R5C3467, locked for R5

2. 45 rule on R12 2 innies R2C28 = 8 = [53/62/71], clean-up: no 4,5,9 in R3C2

3. 45 rule on R89 2 innies R8C28 = 5 = {14/23}, clean-up: no 1,2 in R7C8

4. 45 rule on N7 2 innies R7C1 + R8C3 = 17 = {89}, locked for N7
4a. 5,7 of 29(5) cage locked in R8C4 + R9C45, locked for N8, clean-up: no 8 in R7C7

5. Killer pair 8,9 in R7C1 and R7C67, locked for R7

6. 45 rule on N3 2 innies R2C7 + R3C9 = 12 = {39/48/57}, no 2,6

7. R8C567 = {269/368/467} (cannot be {179/278/359/458} because 5,7,8,9 only in R8C7), no 1, 6 locked for R8C567, clean-up: no 2 in R9C9
7a. 7,8,9 only in R8C567 -> R8C7 = {789}
7b. 6 locked in R8C56, locked for N8, clean-up: no 9 in R7C7
7c. Killer pair 8,9 in R8C4 + R9C45 and R7C6, locked for N8

8. 45 rule on C1234 3 outies R279C5 = 1 innie R4C4 + 1
8a. Min R279C5 = 8 -> min R4C4 = 7
8b. Max R4C4 = 9 -> max R279C5 = 10 -> max R27C5 = 5, R2C5 = {1234}
8c. Min R27C5 = 3 -> max R9C5 = 7

9. 3 in C4 locked in R12C4, locked for N2
9a. 6 in C4 locked in R23C4, locked for N2

10. R279C5 = R4C4 + 1 (step 8)
10a. R279C5 = {125/127/145}, 1 locked in R27C5 for C5
10b. R279C5 = 8 or 10 -> no 8 in R4C4

11. 45 rule on C1 4 innie R3489C1 = 12 = 12{36/45}, no 7,8,9

12. R567C1 = {389/479/578} (cannot be {569} which clashes with R12C1), no 6
12a. 4,5 of {479/578} must be in R6C1 -> no 7 in R6C1

13. 45 rule on R789 2 innies R7C19 = 1 outie R6C4 + 9
13a. Max R6C4 = 4 -> max R7C19 = 13, max R7C9 = 5

14. 45 rule on R89 3 outies R7C238 = 14 = {257/347/356} (cannot be {167} which clashes with R7C7), no 1

15. Hidden killer quad 5,7,8,9 in R8C19, R8C34 and R8C7 -> R8C19 must contain 5/7
15a. 5 in R8 locked in R8C149
15b. 45 rule on R9 4 outies R8C1349 = 23 = {1589/2579/3578}, no 4

16. Hidden killer pair 8,9 in R8C7 and R9C78 for N9, R9C78 must contain 8/9 (cannot contain both) -> R8C7 = {89}, clean-up: no 4 in R8C56 (step 7)
16a. R9C678 = {159/168/249/258/348} (cannot be {267/357/456} which donít contain 8,9), no 7
16b. 1 of {159/168} must be in R9C6 -> no 1 in R9C78

17. Naked pair {89} in R8C37, locked for R8
17a. Naked pair {57} in R8C4 + R9C5, locked for N8

18. 4 in R8 locked in R8C28 = {14}, locked for R8, clean-up: no 4,5 in R7C8, no 7 in R9C9

19. R7C238 (step 14) = {347/356} (cannot be {257} because R7C8 only contains 3,6) = 3{47/56}, no 2, 3 locked for R7

20. 45 rule on N5 4 innies R4C4 + R5C46 + R6C4 = 13 = {1246/1345} (cannot be {1237} because 3,7 only in R4C4) = 14{26/35}, no 7, 4 locked for N5
20a. 3,6 only in R4C4 -> R4C4 = {36}

21. 12(3) cage at R3C5 = {138/156/237/246/345} (cannot be {129/147} because R4C4 only contains 3,6), no 9
21a. 1 of {138} must be in R3C6 -> no 8 in R3C6

22. 25(4) cage at R1C5 = {1789/3589/4579}, no 2

23. 45 rule on N4 2 outies R37C1 = 1 innie R5C3 + 7
23a. Min R37C1 = 9 -> min R5C3 = 2, clean-up: no 5 in R5C4
23b. Max R5C3 = 5 -> max R37C1 = 12, max R3C1 = 4

24. Naked triple {124} in R567C4, locked for C4 -> R1C4 = 3
24a. Naked triple {12} in R1C23, locked for N1

25. Min R2C45 = 6 -> max R2C3 = 7

26. 3 in N1 locked in R2C3 + R3C1
26a. 45 rule on N1 3 remaining innies R2C3 + R3C13 = 16 = {349/358/367}
26b. 8 of {358} must be in R3C3 -> no 5 in R3C3, clean-up: no 9 in R3C4
26c. 7 of {367} must be in R2C3 -> no 6 in R2C3

27. 45 rule on N6 2 outies R37C9 = 1 innie R5C7 + 9
27a. Min R37C9 = 10 -> no 3,4,5 in R3C9 (R37C9 cannot be [55]), clean-up: no 7,8,9 in R2C7

28. 25(4) cage at R1C5 (step 22) = {3589/4579} (cannot be {1789} because only 3,4,5 in R2C7), no 1, 9 locked for N2, CPE no 5 in R2C4

29. R2C345 = {148/157/238/247/256/346}
29a. 7 of {157/247} must be in R2C4 -> no 7 in R2C3, clean-up: no 6 in R3C3 (step 26a), no 8 in R3C4

30. Killer pair 8,9 in R38C3, locked for C3

31. Hidden killer pair 1,2 in R2C5 and R3C56 for N2, R3C56 must contain 1/2 (cannot contain both) -> R2C5 = {12}

32. 45 rule on C123 6 innies R1C2 + R12358C3 = 29, R1C23 = 3, R38C3 = 17 -> R25C3 = 9 = {45}, locked for C3, clean-up: no 4 in R5C4

33. R3C1 = 3 (hidden single in N1)

34. R567C1 (step 12) = {479/578} -> R5C1 = 7, clean-up: no 6 in R12C1
34a. 4,5 only in R6C1 -> R6C1 = {45}

35. Killer pair 4,5 in R12C1 and R6C1, locked for C1 -> R8C1 = 2, clean-up: no 9 in R8C7 (step 7), no 6 in R9C9

36. R8C7 = 8 (naked single), R8C3 = 9, R9C4 = 8, R7C6 = 9, R7C7 = 6, R78C8 = [34], R7C1 = 8, R6C1 = 5, R5C34 = [42], R4C6 = 6, R5C6 = 1 (both step 20), R5C7 = 5, R6C4 = 4, R7C12 = [12], R7C9 = 5, R7C23 = [47], R8C2 = 1, R8C56 = [63], R9C6 = 4, R89C9 = [71], R8C4 = 5, R9C5 = 7, R3C34 = [86], R2C345 = [571], R1C23 = [21], R23C2 = [67], R4C123 = [182], R9C123 = [653], R4C4 = 9, R3C9 = 9, R2C8 = 2, R9C78 = [29], R2C6 = 8, R1C6 = 5, R3C56 = [42], R1C5 = 9, R12C1 = [49], R3C78 = [15], R1C7 = 7, R6C36 = [67], R4C8 = 7

37. R5C2 = 9 (hidden single in R5)

and the rest is naked singles and cage sums
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azpaull
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Joined: 27 Aug 2007
Posts: 14
Location: Arizona

PostPosted: Fri Dec 07, 2007 8:46 pm    Post subject: Reply with quote

I enjoyed this - as I do any Assassin that I can finish! Because it took less combo-crunching, I'll put this at a fun 0.75! (Keep mixin' 'em up, Ruud! Thanks.)
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