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TJK 33

 
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Para
Yokozuna
Yokozuna


Joined: 08 Nov 2006
Posts: 384
Location: The Netherlands

PostPosted: Sun Nov 18, 2007 8:24 pm    Post subject: TJK 33 Reply with quote

Hi

This was a fun puzzle. About the difficulty level i like for a Texas Jigsaw Killer. Not too hard but needs that extra bit of thinking. My walk-through is the revised version, took out a lot of steps and analysis out that wasn't really necessary. Also edited the order a bit. In the end the clean up kinda disappeared.


Walk-through TJK 33

Nonet Numbering:
111222223
411222323
441155333
441155333
444555566
774775666
777788866
999788866
999999888


1. 20(3) at R1C3, R4C1 = {389/479/569/578}: no 1,2

2. 13(4) at R1C6 = {1237/1246/1345}: no 8,9; 1 locked for N2

3. 10(3) at R1C9 = {127/136/145/235}: no 8,9

4. 22(3) at R4C6 = {589/679}: no 1,2,3,4; 9 locked -> pointing R4C5 + R5C7: no 9

5. 18(5) at R5C4 = {12348/12357/12456}: no 9; 1,2 locked -> pointing R6C6: no 1,2

6. 11(3) at R5C8 = {128/137/146/236/245}: no 9

7. R67C9 = {59/68}: no 1,2,3,4,7

8. 19(3) at R8C8 = {379/478}: {289/469/568} blocked by R67C9: no 1,2,5,6; 7 locked in cage -> pointing: R5C9, R8C567: no 7
8a. Killer Pair {89} in R67C9 + 19(3) cage -> pointing: R5C9: no 8.9

9. 45 on C9: 3 outies: R348C8 = 21 = {489/579/678}: no 1,2,3

10. 45 on C6789: 2 innies: R38C6 = 5 = {14/23}

11. 45 on N1: 2 innies: R1C3 + R4C4 = 10 = {37/46}/[82/91]: no 5; R4C4: no 8,9

12. 19(5) at R5C2 = {12349/12358/12367/12457/13456}: 1 locked.
12a. 1 locked in 19(5) and 18(5) at R5C4: 1 locked within R5C2345 + R6C3 and R6C245 + R7C23 -> 1 locked for N7 within R6C245 + R7C23

13. LOL R89: R8C489 = R7C567: no 1

14. LOL R6789: R5C89 = R6C36: no 9
14a. (from step 12a.) 1 locked within R5C234589 for R5 -> R5C7: no 1
14b. 18(3) at R5C7 = [279]/{36}[9]/{45}[9]/{378/468/567}: no 1; R6C7: no 2

15. 45 on N3: 1 outie and 4 innies: R2C8 + 22 = R3C8 + R4C789: R2C8: no 9

16. 45 on C89: 3 innies: R129C8 = 13
16a. Cageoverlap: R19C8 = R23C7
16b. LOL C89: R2346C7 = R129C8 + R9C9
16c. From step 16a.:LOL C89: R19C8 = R23C7; R2C8 + R9C9 = R46C7: no 2
16d. When R9C9 = 9, R6C7 = 9(hidden single N6) -> R4C7: no 9(When R9C9 no 9, R4C7 no 9 through LOL C89)
16e. 9 in 22(3) at R4C6 locked for C6 and N5

17. 9 in N6 either in R6C7, 14(2) at R6C9 or 19(3) at R8C8
17a. R6C7 -> R9C9 = 9(step 16b), so either 14(2) = {59} or 19(3) = {739}: R6789 = {3|5..}
17b. 10(3) at R1C9 = {127/136/145}: {235} blocked by step 17a.: 1 locked for C9 and N3
17c. Clean up: R19C8: no 1(LOL C89)

18. 13(3) at R2C7 = {238/247/256/346}: no 9
18a. Clean up: R8C9: no 9(LOL C89)

19. 9 in N3 locked within 23(4) at R3C8 -> 23(4) = {2489/2579/3569} = {2|3..}(in R45C9),{4|5..}: {3479} blocked by 10(3) at R1C9
19a. 10(3) at R1C9 = {127/136}= {2|3..}: {145} blocked by 23(4): no 4,5
19b. Killer Pair {23} in 10(3) at R1C9 + R45C9 -> locked for C9
19c. 19(3) at R8C8 = {478}: no 9 -> pointing: R567C9 + R8C567: no 4,8
19d. R67C9 = {59}(last combo) -> locked for C9 and N6
19e. Jigsaw Triple {478} in R7C567(LOL R89) + R9C9 -> locked for N8
19f. R7C567 can't use 3 of {478} -> R8C4: no 4,7,8(LOL R89)
19g. Clean up: R23C7: no 8(LOL C89); R6C36: no 5(LOL R6789)

20. 45 on R789: 4 innies: R7C2389 = 14 = {126}[5]/{234}[5]: no 7,8,9; R7C9 = 5; 2 locked for R7
20a. 1 in R7 locked within innies: R7C238 = {126} -> locked for R7
20b. R6C9 = 9
20c. Clean up: R8C4: no 2,5,6(LOL R89)

21. 11(3) at R5C8 = {128/137/146} = {4|7|8..}: {236} blocked by R5C9
21a. Killer Triple {478} in 11(3) at R5C8 + R8C89 -> locked for N6
21b. Clean up: R2C8 = {36}; R4C7 = {78}; R9C9 = {78} (all through LOL C89)
21c. 4 in R9 locked for N9
21d. 4 in R8 locked for N6
21e. 4 in N8 locked for R7
21f. 4 in N7 locked for R6
21g. Clean up: R567C8: no 6; R45C6: no 7,8

22. 45 on N9: 1 innie and 2 outies: R9C9 + 7 = R7C4 + R9C6: R7C4 + R9C6 = [95/86/87/96]: [78] blocked by IOU: R7C4 = {89}; R9C6 = {567}

23. LOL R89: R7C567 needs 2 of {478} and 1 of {39}
23a. 18(3) at R9C6 = [792]/[7]{56}: [693] blocked by R7C567; R9C6 = 7; R9C7 = {569}; R9C8 = {256}
23b. R9C9 = 8; R6C6 = 8; R7C4 = 8(step 29); R6C6 = 8(hidden)
23c. R4C7 = 8(hidden); R5C8 = 8(hidden)
23d. Clean up: R45C6 = {59} -> locked for C6 and N5

24. 9 in C7 locked for N8

25. 14(3) at R7C6 = [491]: {347} blocked by R7C5; [392] blocked by step 23(LOL R89)
25a. R7C5 = 7(hidden); R7C1 = 3; R8C4 = 9

26. 6 in C9 locked within R12345C9 -> CPE: R34C8: no 6
26a. 6 in C8 locked within R129C8 -> locked within R236C7(LOL C89) for C7
26b. R9C78 = [56]; R2C8 = 3; R6C7 = 3(LOL C89); R5C7 = 7; R5C9 = 6(hidden)
26c. 6 in R7 locked for N7
26d. R6C3 = 6(hidden); R7C2 = 6(hidden); R8C1 = 6; R8C2 = 8; R8C3 = 5(hidden)

Now it is really down to basics.

27. 23(4) at R3C8 = 6{59}[3] -> R4C9 = 3; R34C8 = {59} -> locked for C8
27a. R8C9 = 4(hidden); R8C8 = 7; R1C8 = 4(hidden); R1C7 = 2
27b. R12C6 = {16} -> locked for N2 and C6

28. 20(3) at R1C3 = [8]{57}: R1C3 = 8; R12C4 = {57} -> locked for C4 and N2
28a. R12C5 = [98]; R6C5 = 5(hidden); R1C6 = 6(hidden); R2C7 = 6(hidden)
28b. R2C6 = 1; R3C7 = 4; R1C2 = 3(hidden); R5C3 = 3(hidden); R9C4 = 3(hidden)
28c. R9C5 = 4; R5C4 = 4(hidden)

29. 6 in C5 locked for 29(6) cage at R1C5
29a. R4C5 = 6(hidden); R3C4 = 6(hidden)
29a. R34C3 = {17}(last combo within 14(3)) -> locked for C3 and N1

And the rest is all naked singles.

greetings

Para


Last edited by Para on Mon Feb 25, 2008 1:01 pm; edited 1 time in total
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Caida
Hooked
Hooked


Joined: 03 Nov 2007
Posts: 38
Location: Canada

PostPosted: Fri Nov 30, 2007 1:34 pm    Post subject: my walkthrough for TJK #33 Reply with quote

I had started this walkthrough and kept getting stumped so I went through Para's walkthrough looking for clues as to where I could go next.

I found that I didn't see Para's step 12 and 14a & b - so had to get an explanation. (Thanks Para!!!)

Armed with the explanation I needed, I tackled the puzzle again. I did use Para's step 12 and 14a&b (my step 1), but I think I came up with a different enough solution path that I am posting it below.

Any comments/suggestions/corrections are always appreciated!!

Caida


TJK #33 Walkthrough

Nonets:

111222223
411222323
441155333
441155333
444555566
774775666
777788866
999788866
999999888


Preliminaries:

a. 20(3)n12 and n47 = {389/479/569/578} (no 1,2)
b. 13(4)n2 = {1237/1246/1345} (no 8,9) 1 locked for n2 in 13(4) -> no 1 elsewhere in n2
c. 10(3)n3 = {127/136/145/235} (no 8,9)
d. 22(3)n53 = {589/679} (no 1..4) -> no 9 in r4c5 or r5c7 (common peers)
e. 11(3)n6 = {128/137/146/236/245} (no 9)
f. 14(2)n6 = {59/68} (no 1..4,7)
g. 19(3)n68 = {289/379/469/478/568} (no 1)
h. 18(5)n547 = {12348/12357/12456} (no 9) -> no 1,2 in r6c6 (common peers)

My step 1 is steps 12, 13, and 14a&b in Para’s walkthrough (Thanks Para for helping me to see this!!)
1. 19(5)n47 = {12349/12358/12367/12457/13456}
1a. -> 18(5)n547 and 19(5)n47 both require 1 (prelim h)
1b. r7c14 and r8c4 no 1 (common peers)
1c. 1 is locked in n7 within either 18(5) or 19(5); therefore one of the 1s in 18(5) and 19(5) must be in n7 (group 1)
1d. therefore the other 1 must be in r5c2345 + r6c3 (group 2); meaning either there is a 1 in r5c2345 OR in r6c3
1e. LOL move on r6789: r5c89 = r6c36; this means that if there is a 1 in r6c3 then there MUST be a 1 in r5c89
1f. -> and if there is NOT a 1 in r6c3 then there must be a 1 in r5c2345 (step 1f)
1h. -> 1 locked for r5 in r5c234589; no 1 in r5c7
1d. LOL r89: r7c567 = r8c489; no 1

2. 19(3)n68 = {379/478} (other combinations {289/469/568}blocked by 14(2)n6)
2a. -> 19(3)n68 no 2,5,6
2b. -> r5c9 and r8c567 no 7 (common peers)
2c. killer pair {89} in 19(3)n68 and 14(2)n6
2d. -> r5c9 no 8,9 (common peer)

3. Innies r789: r7c2389 = 14(4) = {1238/1256/1346/2345} (no 7,9)
Note: combo 1247 not possible because of r7c9
3a. r7c238 no 8 (any 8 must be in r7c9)
3a. cleanup: r6c9 no 5

4. Outties c9: r348c8 = 21(3) = {489/579/678} (no 1..3)

5. Innies c6789: r38c6 = 5(2) = {14/23} (no 5..9)

6. 14(2)n6 and 19(3)n68 = {59}/{478} or {68}/{379}
6a. -> either r7c9 contains a 5 OR r89c9 contains a 3
6b. -> this blocks combo {235} from 10(3)n3
6c. -> 10(3)n3 = {127/136/145} -> 1 locked for n3 and c9

7. Innies and Outties n6: r5c9 + r6c7 – r9c9 = 1
7a. -> r6c7 no 1, 9
7b. 1 now locked in 11(3)n6 for c8 = {128/137/146} no 5

8. LOL r6789: r6c36 = r5c89 (step 1e) no 9

9. 18(3)n56 = {378/468/567} no 2

10. Innies and Outies n3: r3c8+r4c789 – r2c8 = 22
10a. ->max r3c8+r4c789 = {6789} = 30; max r2c8 = 8 (no 9)
10b. LOL c789: r1c78+r2c8+r5c7 = r78c56 no 9
10c. r9c9 no 9 (CPE with all 9s in n6)

11. Innies c89: r129c8 = 13(3) = {238/247/256/346} (no 9)
11a. LOL: c89: r2346c7 = r129c8+r9c9 (no 9)
11b. -> 9 locked in 22(3)n53 within r45c6 - > no 9 elsewhere in n5 or c6

12. 9 locked in n3 in 23(4)n36 = {2489/2579/3569}
Note: {3479} blocked by 10(3)n3
12a. 10(3)n3 = {127/136} no 4,5
Note: combo {145} blocked by 23(4)n36
12b. killer pair {23} locked in 10(3)n3 and 23(4)n6 for c9 -> no 2,3 elsewhere in c9
12c. 19(3)n68 = {478} no 9 -> no 4,8 in r567c9 or r8c567 (CPE)
12d. 14(2)n6 = [95]
12e. 23(4)n36: r34c8 no 6,7 (combos with 6 or 7 {3569/2579} – must have {59} in r34c8 b/c of 14(2)n6)

13. Innies n1: r1c3+r4c4 = 10(2) = {19/28/37/46} (no 5)
13a. r4c4 no 8,9

14. revisit of step 3: Innies r789: r7c238 = 9(3) = {126/234}
14a. 2 locked for r7 in c238
14b. LOL r89: r7c567 = r8c489; no 2,5

15. looking again at the 19(3)n68
15a. -> if r9c9 = 4 then 4 in n9 is in r8c123; if r9c9 <> 4 then r8c89 = 4 then 4 in n9 is in r9c123456
15b. -> no possibility of 4 in r9c78 or r8c4
15c. same can be said of 7 and 8
15d. summarizing: r9c78 and r8c4 no 4,7,8

16. revisit of step 7: Innies and Outties n6: r5c9 + r6c7 – r9c9 = 1
16a. -> max of r9c9 = 8; max of r5c9+r6c7 = 9
16b. -> r6c7 no 4, 8

17. 5 locked in r6 for n7 -> no 5 elsewhere in r6

18. revisit of step 9: 18(3)n56 = {378/468/567}
18a. -> no 6 in r5c7 (either 6 is in r6c7 for {468} or 5 is in r5c7 for {567})

19. if 10(3)n3 = {136} then r5c9 = 2 otherwise 10(3)n3 = {127}
19a. r4c9 no 2

20. 18(3)n98 = [792/396/693/495/756/765]
20a. r9c6 = {3467} no 1,2,5,8; r9c7 = {569} no 1,2,3
20b. 1 locked in r9 in n9

21. Innies and Outties n8: r7c4 + r9c6 – r9c9 = 7
21a. -> r7c4 no 3,6,7; r9c6 no 4

22. re-revisit of step 3(and 14): Innies r789: r7c238 = 9(3) = {126/234}
22a. 1 locked for r7 in c238
22b. -> r7c278 = {126} -> locked for r7
22c. LOL r89: r7c567 = r8c489; no 6

23. 11(3)n6 = {128/137/146} and r8c89 must contain 2 of {478}
23a. -> killer triple {478} locked in n6 in 11(3)n6 and r8c89
23b. -> r6c7 no 7

24. re-revisit of step 9(and step 18): 18(3)n56 = {378/468/567}
24a. r5c7 and r6c6 = {78/48}/[57] no 3,6
24b. looking at 22(3)n35 and 18(3)n56
24c. -> r4c7 no 5,6 -> blocked by 18(3)n56
24d. ->cleanup: r45c6 no 7,8

I’m not sure if this step wound up be necessary – but I was pleased with myself for spotting it
25. within n3 7 and 8 are locked in 10(3) 23(4) and r4c7 (if 10(3)={127} then r4c7 = {8}; if 10(3)= {136} then 23(4)in n6 = {489/579} and r4c7 = {7/8}
25a. -> r23c7 no 7,8

26. Outies r9: r8c4589 = 25(4) = [59]{47}

Now everything falls into place

26a. r9c9 = 8
26b. 11(3)n6 = {128}
26c. 23(4)n36 = {3569}
26d. 10(3)n3 = {127}
26f. r8c89 = [74]
26g. 22(3)n35 = {589}
26h. HS: r9c7 = 5 -> 18(3)n98 = [756]
26i. 12(3)n9 = {129}
26j. 18(3)n56 = [783]
26k. r45c9 = [36]
26l. 17(3)n79 = [3]{68}
26m. 14(3)n8 = [491]
26n. 20(4)n78 = [87]{23}
26o. HS: r5c8 = 8
26p. 13(4)n2 = {1246}
26q. r12c8 = [43]; r1c7 = 2
26r. 20(3)n12 = [8]{57}
26s. r12c5 = [98]
26t. HS: r1c2 = 3; r5c3 = 3; r9c4 = 3
26u. HS: r5c4 = 4; r6c5 = 5
26v. 18(5)n457 = {12456} no 7
27w. 19(5)n47 = {12367} no 4
27x. 20(3)n47 = [794]
27y. 19(4)n4 = {2458}
27z. Everything left is now singles

Solution:

538796241
294581637
857613492
741269853
913425786
476158329
362874915
685932174
129347568
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