Today's Nightmare can be solved with basic methods and a single Unique Rectangle.
If you do not use the UR, the solution is much tougher.
David, is there a constellation lurking in this particular UR?
(I came late to solve May 11, and found I was early to May 12!)
Best wishes,
Keith
May 12, 2006: Do you UR?
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"Constellations" vs ""UR"s
Yes. There's always a "constellation" (or some similar configuration) buried outside every "UR" -- it has to be there, or else the solution would not be unique. The challenge is finding a pattern that's compact enough to be easily understood.keith wrote:David, is there a constellation lurking in this particular UR?
After a series of mostly routine moves (including some fancy coloring on the digit "6", and an XY-Wing from r5c6) I arrived at this position.
Code: Select all
1 46 27 27 8 5 3 9 46
39 5 29 234 36 46 7 18 18
347 346 8 9 37 1 456 25 246
239 239 4 5 1 789 28* 6 37
8 239 1 47 679 46 24 37 5
6 7 5 48 2 3 9 18 148
4579 489 79 6 359 2 1 357 378
2579 128 3 178 579 789 568 4 2678
257 128 6 1378 4 78 58 2357 9
In this case the chains proceeding from two of the "conjugate" cells (r1c9 & r6c4) are ridiculously long. I had my best luck (a "6-stars constellation") working from r5c7.
A. r5c7 = 4 ==> r5c4 = 7 ==> r5c8 = 3
B. r5c7 = 4 ==> r6c4 = 4
C. (r6c4 = 4 & r5c4 = 7) ==> r1c4 = 2 ==> r2c4 = 3
But with "3"s in columns 4 & 8 it becomes impossible to enter a "3" in row 9. Therefore r5c7 = 2, and the rest of the puzzle is straightforward.
Our friend ravel presented a fascinating analysis of the May 11 nightmare in another discussion forum. Briefly, he found not only a "UR", but also a [non] Unique Hexagon on his way to the solution. dcbkeith wrote:(I came late to solve May 11, and found I was early to May 12!)