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23 January X-treme - JOAX!

 
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sudokuEd
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PostPosted: Sat Feb 03, 2007 6:29 am    Post subject: 23 January X-treme - JOAX! Reply with quote

Been lots of very high rating X-files for January - this X-treme from 23 Jan is the highest at 37000+. So have dubbed this JOAX.

History demands we give it a whirl shakng2 .

From here: [edited to fix mistake in code referred to in following posts]
Code:
.------------------------.------------------------.------------------------.
| 2       35678   3578   | 4       35678   68     | 3567    1       9      |
| 45678   1       34578  | 2       356789  689    | 34567   45678   34     |
| 9       345678  34578  | 35678   35678   1      | 24567   2345678 234    |
:------------------------+------------------------+------------------------:
| 467     234567  234579 | 359     234569  246    | 1       234569  8      |
| 14568   234568  1234589| 35689   458     7      | 234569  234569  234    |
| 4568    234568  234589 | 1       2345689 489    | 234569  234569  7      |
:------------------------+------------------------+------------------------:
| 4578    9       24578  | 678     24678   2468   | 347     2347    1      |
| 1478    2478    6      | 789     124789  3      | 2479    479     5      |
| 3       247     1247   | 79      12479   5      | 8       2479    6      |
'------------------------'------------------------'------------------------'


1. no 2 in r 4c8
1a. 2 in r4c6 -> no 2 in r4c8
1b. 2 in r7c6 -> 2 in D/ in r3c7 or r8c2 -> cross-over: no 2 in r8c7 -> 2 in n9 in r9c8 -> no 2 in r4c8

2. no 2 in r7c3
2a. 2 in r7c6 -> no 2 in r7c3
2b. 2 elsewhere in n8 only in c5 -> 2 in D/ in r4c6 -> no 2 in r7c3

3. 2 cannot be in r9c5
3a. means 2 in both r8c2 and r4c6: 2 2's in D/

4. no 5 in r46c5
4a. 5 in r3c4 -> 5 in D/ in r5c5 -> no 5 in r46c5
4b. 5 elsewhere in n2 in c5 -> no 5 in r46c5

5. no 8 in r6c1
5a. 8 in r2c8 -> 8 in r78c1 -> no 8 r6c1
5b. 8 in r3c8 -> 8 in D\ in r5c5 or r6c6.
5c. from 5b. 8 in r5c5 -> 8 in r78c1 -> no 8 r6c1
5d. from 5b. 8 in r6c6 -> no 8 in r6c1


Last edited by sudokuEd on Sat Feb 03, 2007 10:47 pm; edited 1 time in total
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Para
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Joined: 08 Nov 2006
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PostPosted: Sat Feb 03, 2007 11:07 am    Post subject: Reply with quote

37.000+??? how the hell do you get a puzzle to a 37000+ rating? That can seriously not be good for our health. Let's see what we can make of this.

Para
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rcbroughton
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PostPosted: Sat Feb 03, 2007 3:08 pm    Post subject: Reply with quote

Hi guys

taking a break from Ed's killer - not really sure what 37000 means, except we're probably expecting some nasty moves ahead?.

Anyway here's a couple of quick moves for you:

[Edited to reflect Para picking up I'd missed a "5" at r5c5]

no longer valid
6. No 5 in r3c4
6a. r3c4=5 -> r3c3<>5 => r4c4=5 (D\) -> r3c4<>5

7. 5 lnow locked in N2 for c5


8. no 5 at r4c1
8a. r4c1=5 -> r7c1<>6 -> r7c3=5 -> r3c3<>5 => r4c4=5 -> r4c1<>5

no longer valid
9. no 5 at r4c3
9a. r4c3=5 -> r3c3<>5 => r4c4=5 (D\) -> r4c3<>5

10. no 8 at r3c3
10a Placing 8 at r3c3 eliminates all candidates for 8 in column 8
10b. r3c3=8-> r3c8<>8
10c r3c3=8-> r3c3=8 -> r5c5=4 -> r6c6=9 -> r8c8=7 -> r7c7=3 -> r4c4=5 -> r7c6=4 -> r7c8=2 -> r4c6=2 -> r8c2=8 -> r2c8<>8
10d. no other cells with 8 in column 8

11. 8 now locked for D\ in n5

12. Placing 8 at r3c4 forces 2 cells to 9 in row 8
12a. r3c4=8 -> r8c4={79}, r2c8=8 -> r5c5=4 -> r8c8 = {79}
12b. r3c4=8 -> r1c6=6, r2c8=8 -> r5c5=4 -> r4c6=2 ->r8c2=7 -> r8c48 both forced to 9


13. placing 2 at r3c7 leaves no 2 in n5 or c6
13a. r3c7=2 -> r4c6<>2, r8c27<>2 -> r8c5=2 -> r6c5<>2, r7c6<>2

14. no 2 at r4c2
14a. r4c2=2 -> r4c6<>2 => r8c2=2 -> r4c2<>2

Richard


Last edited by rcbroughton on Sat Feb 03, 2007 7:07 pm; edited 1 time in total
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Para
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PostPosted: Sat Feb 03, 2007 4:19 pm    Post subject: Reply with quote

There seem to be some typo's in your code Ed. There are still 9's in R1, C9, N3 and D/.

And i wondered about the 5 in R4C1 but i see how it works over D\ now.

Now to find somethings useful.

Para
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Para
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PostPosted: Sat Feb 03, 2007 4:26 pm    Post subject: Reply with quote

rcbroughton wrote:

6. No 5 in r3c4
6a. r3c4=5 -> r3c3<>5 => r4c4=5 (D\) -> r3c4<>5


5 can be in R5C5, right on D\? and then there is no contradiction

This messes up a few of your moves. 7, 9, 10 and 11 don't work now.

8 and 12-14 are still ok.

rcbroughton wrote:
12. Placing 8 at r3c4 forces 2 cells to 9 in row 8
12a. r3c4=8 -> r8c4={79}, r2c8=8 -> r5c5=4 -> r8c8 = {79}
12b. r3c4=8 -> r1c6=6, r2c8=8 -> r5c5=4 -> r4c6=2 ->r8c2=7 -> r8c48 both forced to 9


for 12 you need a small edit
12a. r3c4=8 -> r8c4={79} -->> R7C4 = 6 -->> R45C4= {35} -->> r2c8=8 -> r5c5=4 -> r8c8 = {79}


Para
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Para
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PostPosted: Sat Feb 03, 2007 4:58 pm    Post subject: Reply with quote

15. No 3 in R3C8 because of 3's in C4
15a. R3C4 = 3 --> no 3 in R4C8
15b. R4C4 = 3 -->> R7C8 = 4 --> no 3 in R4C8
15c. R5C4 = 3 -->> R23C9 = 3 --> no 3 in R4C8
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rcbroughton
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PostPosted: Sat Feb 03, 2007 7:02 pm    Post subject: Reply with quote

Para

thanks - I clearly transposed something wrong from Ed's code - I ended up without a 5 at r5c5.

I'll edit my post - only steps 8, 13 and 14 valid at this point.

I also noted a few odditied in Ed's codes - so, to summarise up to end of move 15 - but not including 6,7,9,10,11,12 - I think that leaves us here.

Code:
.-------------------------------.-------------------------------.-------------------------------.
| 2         35678     3578      | 4         35678     68        | 3567      1         9         |
| 45678     1         34578     | 2         356789    689       | 34567     45678     34        |
| 9         345678    34578     | 35678     35678     1         | 4567      245678    234       |
:-------------------------------+-------------------------------+-------------------------------:
| 467       34567     234579    | 359       23469     246       | 1         34569     8         |
| 14568     234568    1234589   | 35689     458       7         | 234569    234569    234       |
| 456       234568    234589    | 1         234689    489       | 234569    234569    7         |
:-------------------------------+-------------------------------+-------------------------------:
| 4578      9         4578      | 678       24678     2468      | 347       2347      1         |
| 1478      2478      6         | 789       124789    3         | 2479      479       5         |
| 3         247       1247      | 79        1479      5         | 8         2479      6         |
'-------------------------------.-------------------------------.-------------------------------'


That leads me to one next move:

16. No 7 at r7c5 - placing 7 at r7c5 eliminates all candidates for 7 in D/
16a r7c5=7 -> removes 7 from D/ at r7c3
16b r7c5=7 -> r9c4=9 -> r8c4=8 -> r7c4=6 -> r3c4=7 -> r8c8=7 -> removes remaning 7's from D/ at r8c2 and r2c8
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Para
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PostPosted: Sat Feb 03, 2007 7:37 pm    Post subject: Reply with quote

12 still works if you use the edit i posted. so that one should remain valid. Because the edit eliminates the 5 from R5C5 so the rest of the steps are still valid so the 8 can be removed from R3C4.

12. Placing 8 at r3c4 forces 2 cells to 9 in row 8
12a. r3c4=8 -> r8c4={79} -->> R7C4 = 6 -->> R45C4= {35} -->> r2c8=8 -> r5c5=4 -> r8c8 = {79}
12b. r3c4=8 -> r1c6=6, r2c8=8 -> r5c5=4 -> r4c6=2 ->r8c2=7 -> r8c48 both forced to 9

Para
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rcbroughton
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PostPosted: Sat Feb 03, 2007 8:07 pm    Post subject: Reply with quote

Para

agreed! 8 comes out of r3c4 - my move 12 doesn't work but your move 12 does. Credit to you for seeing a more complex move.
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