Name That Killer Album

[Ruud]

Here's a puzzle in a series that I started on another forum.

The puzzle requires 2 answers:

1. The solution of the Zero-X-Killer on top.
2. The name of the album below the killer.

I removed artist and title, so you have to browse your CD collection to find it. It was released in 1996.
The killer is Ruudiculous until proven otherwise...



3x3:d:k:4864:4864:5634:56345381:5381:4871:4871:48643594:563453812319:4871:4370:43705634:22:53815657:5657:4370:28:29:30:31:32:33:34:565737:38:39:40:41:42:43259647:48:49:50:513372:4150:4150:4150:57:58:59:4668:4668:4668:5439:41502369:6211:5444:5444:46685439:54396211:6211:6211:5444:2631

Happy hunting and killing!
Ruud

[Nasenbaer]

Sorry, can't help you with the album, I'm not a music freak. But here is the walkthrough for the Album Killer (in tiny font). That was a real tough nut, Ruud.

Walkthrough Album-Killer


0. Preliminary steps
0a. 19(3) at r1c1 and r1c8 : no 1
0b. 6(2) at r1c5 : no 3,6,7,8,9
0c. 22(3) at r3c8 : no 1,2,3,4
0d. 10(3) at r5c1 and r8c9 : no 8,9
0e. 9(3) at r2c7 and r8c3 : no 7,8,9
0f 21(3) at r8c1 : no 1,2,3

1. 45 on N789 : r7c456 = 16(3)

2. 45 on N7 : r8c4 = 1 -> no 4 in r89c3

3. 45 on N9 : r8c6 = 4 -> r89c7 = {89} -> 8,9 locked for c6 and N9

4. 45 on r89 : r8c28 = 5(2) = {23} -> 2,3 locked for r8 -> no 2,3 in r5c5 and r2c28 (from D/ and D\)
4a. no 5,6 in r9c3

5. 2,3 locked in r9c3 and r9c456 for r9 -> 10(3) = {145} -> r8c9 = 5 -> r9c89 = {14} -> 1,4 locked for r9 and N9

6. r89c3 = [62], r8c28 = [32]

7. 3,6,7 locked in r7c789 for r7 a,n N9

8. N7 : 21(3) = {579} -> 5,7,9 locked for N9, 5 locked for r9

9. N8 : 24(4) = {3678} -> 3,6,7,8 locked for N8

10. 45 on N1 : r1c3 + 5 = r4c1 -> r3c1 = {134}, r4c1 = {689}

11. 45 on N3 : r1c7 + 5 = r4c9 -> r3c7 = {1234}, r4c9 = {6789}

12. N36 : 22(3) = 9{58|67} -> 9 locked in 22(3) -> no 9 in r12c9

13. N3 : 19(3) : no 3,6 in r1c8

14. 45 on N2 : r3c5 + 4 = r1c37 -> r3c5 = {123}, r1c37 = 5(2), 6(2) or 7(2)
r3c5 = 1 -> r12c5 = {24}, r1c37 = {14}|[32]
r3c5 = 2 -> r12c5 = {15}, r1c37 = [42]
r3c5 = 3 -> r12c5 = {15}|[24], r1c37 = {34}

15. N3 : 9(3) : no 4 in r23c7

16. 4 is either in r3c123 or in r3c4 for r3 -> no 4 in r1c3
16a. no 9 in r4c1, no 1 in r1c7, no 6 in r4c9

17. N3 : 1 locked for N9 in 9(3) = 1{26|35} -> no 4 in r2c8, no 5 in r2c7

18. from step 14 : no 2 in r3c5, no 3 in r1c7, no 8 in r4c9

19. N3 : 5,6 locked in 9(3) and r3c89 for N3

20. no 4 in r1c12489
20a. r1c7 = 4 -> no 4 in r1c12489
20b. 4 in 19(3) at r1c8 -> (step 14) r1c37 = [32], r12c5 = [42] -> no 4 in r1c12489

21. N23 : 21(4) : must have one of {24} -> 21(4) = {1479|2379|2469|2478|2568|3459|3468} -> one of {89} in r123c6

22. N12 : 22(4) : must have one of {13}, can't have both of {14} (step 14), must have one of {89} -> 22(4) = {1579|1678|3469|3478|3568} -> no 2,3 in r123c4 -> one of {89} in r123c4

23. 3 locked in r2c79 for r2 and N3

24. N36 : 22(3) : no 8 in r3c8

25. N14 : 17(3) : must have one of {68} -> 17(3) = {269|278|368|458|467} -> no 1

26. no 4 in r2c1
26a. 19(3) = {469} : r2c1 = 4 -> r1c7 = 4 -> r4c9 = 9 -> r1c8 = 9 -> r1c12 = {69} not possible
26b. 19(3) = {478} -> 14(3) = {356} with 3 in r3c3 -> r3c5 = 1 -> r1c37 = [14] -> r1c89 = [92] -> r12c5 = [24] not possible

27. N1 : 19(3) : no 7 in r1c1

28. N3 : 19(3) : no 7 in r2c9

29. N1 : no 2 in 19(3)
29a. r2c1 = 2 -> r1c12 = {89} -> conflict with 19(3) in N3
29b. r1c2 = 2 -> r12c1 = [89] -> r4c1 = 6 -> r1c3 = 1 -> r3c5 = 1 -> r12c5 = [24] not possible

30. 2 locked in r3c12 for r3, N1 and 17(3) -> r3c12 = {279}

31. N1 : 19(3) = {568} ({379} blocked by 17(3) -> 5,6,8 locked for N1

32. N1 : 14(3) : no 7 in r3c3

33. 3 locked in r13c3 for c3 and N1

34. N4 : 10(3) = 3{16|25} -> 3 locked in r56c1 for c1 and N4 -> no 4,7 in 10(3)

35. single: r7c1 = 4

36. 4 locked in r6c4 and r5c5 for D/ and N5

37. 5 locked in r456c3 for c3 and N4

38. N4 : 10(3) = {136} -> 1,3,6 locked for N4

39. r4c1 = 8, r1c23 = [83], r7c23 = [18], r6c2 = 6, r3c12 = [27], r9c2 = 5, r6c6 = 8, r5c8 = 8

40. 1 locked in r1c56 for r1 and N2

41. r3c5 = 3, r1c78 = [49], r12c9 = [73], r347c9 = [896], r3c8 = 5, r2c7 = 2, r89c1 = [79], r89c7 = [98], r8c5 = 8, r2c4 = 8, r13c4 = [56], r12c1 = [65], r12c5 = [24], r123c6 = [179], r2c238 = [916], r3c37 = [41], r9c89 = [41], r5c5 = 5, r4c6 = 2, r7c456 = [295], r45c2 = [42], r56c9 = [42], r6c458 = [417], r56c1 = [13], r6c37 = [95], r7c78 = [73], r45c3 = [57], r4c4578 = [3761], r5c467 = [963], r9c456 = [763]


Peter

[rcbroughton]

Still struggling to complete the killer. . .

. . . but the album is "Fashion Nugget" by Cake

Rgds
Richard

[Ruud]

. . . but the album is "Fashion Nugget" by Cake

[rcbroughton]

OK finally got around to finishing it - quite a challenging one.

Posting my walkthrough as there are a few minor differences from [edit] Peter's (oops! - should take a closer look before I post!) - mainly the same through the opening game but a bit different in the middle-game.

1. 45 on n7 - r8c4=1

2. 45 on n9 r8c6=4

3. 45 on r89 r8c28 total 5 = {23}
3a. naked {23} in r8c28 for r8
3b. no 2/3 at r3c2 r3c8 r5c5

4. 9(3) n78 can only be [531]/[621] r9c3={23}
4a naked {23} at r8c8 r9c3 for n7

5. 21(3) n89 can only be 4{89}
5a. {89} locked in 21(3) for n9 and c7

6. 9(3) in n3 - only combo with 4 is {234} - no 4 in r23c7

7.1 only found in r7 in n7
7a 1 locked in 16(3) n7
7b remove from 18(3)n9 in the same row
7c 1 locked in 10(3)n9

8. 10(3) n9. only allowed combo 5{14}/6{13}/7{12} - no 5/6/7 in r9c89

9 must use 7 in 21(3) n7= - 7 locked for n7

10. only combos for 16(4)n7=2{149}/3{148} - no 5/6 in 16(4), must use 4
10a reasoning - can't use {1258}/{1456}/{2356} because it would break the 9(3)n78

11. 4 locked in 16(4)n7 for r7
11a. 4 locked in 10(3)n9 = 5{14} -> r8c3=6 -> r9c4=2 -> r8c2=3 -> r8c8 =2

12. 16(4)n7 = 3{148} - {148} locked for r7

13. 21(3)n7 = {759} with 5 locked for r9

14. 18(4)n9 = 2{367} - {367} locked for r7

15. 24(4)n8={3678}

16. unmarked 16(3)n8 = {259}

17 must use 9 in 22(3)n36 - no 9 in r4c8 r12c9

18 45 on r123 - r4c19 minus r3c5 = 14
18a max r4c19 is 17, so max r3c5=3 ={123}
18b min r3c5 is 1, so max r4c19 is 15 = {69}
18c. r4c19 both limited to {6789}

19 45 on n2 - r1c37 minus r3c5 = 4
19a. 1/2/3, so r1c37 total 5/6/7
19b. no 7/8/9 in r1c3, no 7 in r1c7

20. 19(3)n3 - no possible combo with 3/6 in r1c8

21. 45 n1 r4c1 minus r1c3 equals 5
21a. r4c1 = {689}, r1c3 = {134}

22. 45 n3 r4c9 minus r1c7 equals 5
22a. r1c7 = {1234}

23. 22(3) n36 - no combo with 8 in r3c8

24. 17(3) n14 - no combo with 8 in r3c1

25. 19(3)+9(3) in n3 - no valid combination with 5 in r2c7

26. 19(3)+14(3) in n1 - must use 8 in one or other - no 8 in r3c2

27. 4 locked for r3 in c1-4, all cells can see r1c3,so no 4 in r1c3 -> no 9 in r4c1
27a. (from 18) r4c19=[69]/[87]/[89] - no 6/8 in r4c9 - no 2 in r3c5
27b. (from 22) no 3 in r1c7
27c. (from 19) r1c37=[14]/[32]/[34] - no 1 in r1c7
27d. no 1 in 17(3)n12

28. 3 locked in n3 for r2

29. must use 1 in 9(3)n3={126}/{135}
29a 19(3)n3 combo {568} would conflict with 9(3)n3 - no 5 in r1c8

30. 22(4)n12 - no 3 in r123c4

31. 19(3)&14(3)n1 - {13} in r1c3 restricts combination with 3 at r1c1

32. 14(3)n1 must contain 1 when r1c3=3 and must contain 3 when r1c3=1 - {13} locked in 14(3)+r1c3
32a. 3 locked in n1 for c3
32b. 3 locked in 10(3)n4 = {136}/{235}
32c. 17(3)n12=6{29}/8{27}/8{45}/6{47} - no 6 in r3c12

33. 9(3)&22(3) n3 must use 1,5,6,9 - no 6 in 19(3)n3

34. Placing 1 at r2c5, r2c6 or r3c6 eliminates all possibles for 1 in row 1 (r2c5=1 -> r3c5=3 -> r3c3=1 -> r1c3=3)
34a no 5 in r1c5

35. 4 in r1 can only be at c5 or c789
35a. n3 - 4 in r1 or 4 in r2c9 -> r1c7=2->r1c5=4

36. 19(3)n1 - no 7 in r2c1, no 5 in r1c2

37. cannot place 7 at r4c9
37a r4c9=7 -> r1c7=2->r1c3=3 -> r3c5=1 -> no valid combo in 6(2)n2
37b. r4c9=9 - 22(3)n35=9{67}/[58] -> unmarked cage=23(5)n6
37c. only value 9 at r1c8 n3
37d. 19(3)n3= 9{28}/[73]
37e. only value 4 at r1c7n3
37f. 6(2)n2=[15]/[24]

38. 8 locked in n3 for c9

39. 19(3)&14(3)n1. Only valid combos remove 2 from r2c1, 5,8 from r2c2 8 from r2c3 5,8 from r3c3
39a 8 locked in 19(3)n1

40. (from 19) r1c3=r3c5
40a. r1c3=r3c5=1 -> 6(2)n2=[24]
40b. r1c3=r3c5=3 -> 6(2)n2=[24] since 1 must be used in the 21(4)
40c. 6(2)n2=[24]

41. 19(3)n3=9[82]/[73]

42. 19(3)n1={568} - locked for n1
42a. 14(3)n1=4{19} - {19} locked for r2,n1
42b. 17(3)n14=8{27} - {27} locked for r3
42c. r1c3=3 -> r3c5=3
42d. 22(3)n3=[589]
42e. 19(3)n3=[973]

43. 22(4)n12=3{568} {568} locked for r4 and n2
43a. 21(4)n23=[4179]
43b. 9(3)n3=[261]

44. 23(5)n6=8{1356} r5c8=8

. . . and it all unravels fairly quick from there with singles and cage sums

Rgds
Richard

[Para]

Para's?? I haven't finished this one. Be nicer to Peter all his work.

Para