Hi folks,
Here's the full walkthrough for the V2, based on our tag solution. I incorporated JC's hidden triple in R1, as well as making some minor alterations in the opening sequence.
I also added a couple of missed killer triples (steps 29 and 31c) that changed the course of the game a bit, making it less dependent on conflicting combinations.
Despite several comments to the contrary, the puzzle was not that difficult - certainly not "terrifying", and easily within range of ordinary mortals. Nevertheless, many thanks, Ruud, for providing this V2, thus giving us all a chance to get a small insight into the new JSudoku. Keep those V2's coming!
Talking of JSudoku (my favorite subject at the moment!
), it made heavy going of this puzzle, using no less than 12 XY-chains - despite JC's comment on the Solving Techniques forum that they are
Jean-Christophe wrote:not as useful as I thought
. Not only that, it also hammered those conflicting combinations (especially in columns 4 - 6) time and time again, driving me almost into a state of delirium trying to follow it! Still, I'm looking forward to getting my paws on it as soon as it's out the door.
Now to the walkthrough, which is not in tiny text due to the next Assassin being just a few hours away and the fact that it was a tag solution anyway.
Enjoy!
Assassin 52V2 Walkthrough
1. Innie C5: R5C5 = 1
2. 7/2 at R1C3: no 7,8,9
3. 7/2 at R1C6: no 7,8,9
4. 8/3 at R1C8 = {1(25|34)} (no 6,7,8,9)
4a. 1 locked in 8/3 at R1C8 -> not elsewhere in N3
4b. Cleanup: no 6 in R1C6
5. Hidden triple on {789} in R1 at R1C125 -> R1C125 = {789}
5a. -> R1C125 forms split 24/3 cage in R1 -> R2C8 = 1 (outie, R1)
6. 18/3 at R1C1 = {(29|38)7}
6a. 7 locked in R1C12 -> not elsewhere in R1 and N1
6b. {23} only in R2C2 -> R2C2 = {23}
6c. Cleanup: no 3 in R2C4
7. 10/2 at R2C34 = {28|37|46}: no 5,9
8. 13/2 at R2C6 = {49|58|67}: no 2,3
9. 11/3 at R3C6 = {128|137|146|236|245}: no 9
10. 21/3 at R4C2 = {489|579|678}: no 1,2,3
11. 20/3 at R4C8 = {389|479|569|578}: no 2
12. 10/3 at R8C2 = {127|136|145|235}: no 8,9
13. 6/2 at R8C34 = {15|24}: no 3,6,7,8,9
14. 15/2 at R8C6 = {69|78}: no 1,2,3,4,5
15. 10/2 at R9C3 = {19|28|37|46}: no 5
16. 9/2 at R9C6 = {18|27|36|45}: no 9
17. Outies N1: R12C4 = 8/2 = [17]|{26} = {(1|2)..},{(2|7)..}
({35} blocked because both 3 and 5 unavailable in R2C4)
17a. -> R1C4 = {126} (no 3,4,5), R2C4 = {267} (no 4,8)
17b. Cleanup: R1C3 = {1256} (no 2,3,4), R2C3 = {348} (no 2,6)
18. Outies N3: R12C6 = 9/2 = [18|27|36]|{45}: no 6 in R1C6, no 9 in R2C6
18a. Cleanup: no 4 in R2C7
19. Outies N7: R89C4 = 5/2 = {14}|[23] = {(1|2)..}
19a. -> R8C4 = {124} (no 5), R9C4 = {134} (no 2,6,7,8,9)
19b. Cleanup: R8C3 = {245} (no 1), R9C3 = {679} (no 1,2,3,4,8)
19c. 8 locked in 24/4 at R7C1 = {8..} (no eliminations yet)
20. Outies N9: R89C6 = 13/2 = {67}|[85|94]
20a. -> R9C6 = {4567} (no 1,2,3,8)
20b. Cleanup: R9C7 = {2345} (no 1,6,7,8)
21. Outies C12: R37C3 = 13/2 = {49|58}|[67] (no 1,2,3; no 6 in R7C3)
22. Outies C89: R37C7 = 10/2 = {28|37|46}|[91] (no 5; no 9 in R7C7)
23. Innies C1234: R5C34 = 15/2 = {69|78} (no 2,3,4,5)
24. Innies C6789: R5C67 = 7/2 = {25|34} (no 6,7,8,9)
25. Innies N4: R456C3 = 12/3
25a. min. R5C3 = 6 -> max. R46C3 = 6 -> R46C3 = {(1|2)..}
26. R12C4 and R89C4 form killer pair on {12} in C4 -> not elsewhere in C4
27. {129} now unavailable for 12/3 at R6C3 ({12} only in R6C3)
27a. 12/3 at R6C3 = {138|147|237|156|246|345} (no 9)
28. 9 in C4 now locked in 17/3 at R3C4 = {(17|26|35)9} (no 4,8)
28a. CPE: R5C4 sees all 9's in 17/3 at R3C4 -> no 9 in R5C4
28b. Cleanup: no 6 in R5C3
29. 21/3 at R4C2 must contain exactly 2 of {789} (step 10)
29a. -> R5C3 and 21/4 at R4C2 forms killer triple on {789} in N4
29b. -> no 7,8,9 elsewhere in N4
30. Similarly, R1C2 and 21/4 at R4C2 forms killer triple on {789} in C2
30a. -> no 7,8,9 elsewhere in C2
31. 12/3 at R4C1 = {156|246|345}
31a. -> 12/3 at R4C1 must contain exactly one of {123}
31b. {123} otherwise only available in R46C3
31c. -> 12/3 at R4C1 and R46C3 form hidden killer triple on {123} in N4
31d. -> R4C3 = {123} (no 5), R6C3 = {123} (no 4,5)
31e. Cleanup: no 3 in R34C4 ({359} only combo with 3 (step 28), and {59} now only in R34C4)
32. R12C4 must contain one of {27} (step 17)
32a. -> R12C6 (outies N3, step 18) cannot contain both of {27}
32b. -> no 2 in R1C6; no 7 in R2C6
32c. Cleanup: no 5 in R1C7; no 6 in R2C7
33. Innies - outies, R9: R9C5 (1 innie) = R8C28 (2 outies) + 1
33a. max. R9C5 = 9 -> max. R8C28 = 8 -> no 8,9 in R8C8
33b. min. R8C28 = 3 -> min. R9C5 = 4 -> no 2,3 in R9C5
34. Implication chain eliminates 8 in R2C3
34a. R2C3=8 -> R2C4=2 -> R2C2=3 -> R1C12={78} -> R2C3<>8 (contradiction)
34b. Conclusion: no 8 in R2C3
34c. Cleanup: no 2 in R2C4, no 6 in R1C4 (step 17), no 1 in R1C3
35. 1 in R1 locked in N2, not elsewhere in N2 (R3C6)
35a. min. R34C6 = 5 -> max. R4C7 = 6 (no 7,8)
36. 1 in C3 now locked in N4, not elsewhere in N4
36a. 12/3 at R4C1 = {(26|35)4}, 4 locked for C1 and N4
37. 21/3 at R4C2 = {(59|68)7}, 7 locked for C2 and N4
37a. Cleanup: no 8 in R5C4 (step 23)
38. Hidden single (HS) at R1C1 = 7
39. Naked pair (NP) on {67} in C4 at R25C4 -> no 6,7 elsewhere in C4
40. NP on {59} in C4 at R34C4 -> no 5,9 elsewhere in C4
40a. 17/3 at R3C4 = {359} (step 28)
40b. -> R4C3 = 3
This sets off an avalanche of hidden and naked singles that makes the rest of the puzzle a breeze.