SudoCue Users

Another similar pattern is the Y-Wing (also called W-Wing in Sudopedia ): The 8 at r4 locked at r4c27. Whichever the location, either r5c1 = 5 or r9c7 = 5. Therefore r9c1 <> 5 = 6 Written as an AIC: (5=8)r5c1 - (8)r4c2 = (8)r4c7 - (8=5)r9c7 -> r9c1 <> 5 I personally find it easier to spot than an XY...

Well, the logic is exactly the same, but personally, I find it easier to spot the pattern I mentioned in particular since: it's confined in two adjacent rows and is almost an X-Wing

Note: The skyscraper eliminates 3 from both r2c5 and r5c4 at once

Alternate hint 1: There is also a skyscraper on same digit and location, which is probably easier to spot.

Here is a Windoku Killer. It does not require any hard technique as long as you use the windows and hidden windows. http://img180.imageshack.us/img180/1069/wk3st3.png 3x3:2:k: 5121:5121:2818:2818:2563:2564:2564:3589:3589:5121:4870:4870:2818:2563:7943:7943:7943:3589:3848:4870:3849:3849:5386:5386:7943...

JC, I think that there are some misunderstandings here, respectively some unfortunate phrasing Sorry, I misunderstood the question. My question to you was: Does JSudoku always generate CEs that require Center-Dot Sudoku techniques for solving? No, it does not. Indeed the generator and recursive sol...

Correct,
I noticed 5 new members who joined from April 1st.
However, none were ever posting a message.
Although Ruud removed the "Memberlist" link, the page is still there
My name is Poirot, Hercule Poirot

Which begs the question: Are the clueless puzzles in all your Explosions center-dot? To my recollection, all of Ruud's Explosions that I solved never were. All 9 Sudokus in Clueless Explosions are center-dot by definition. As Ruud explains here (bold text second paragraph :roll: :roll: :roll: ) But...

Yes, I found it easy too. 1a. 17/2 @ r34c9 = {89} (NP @ c9, HW @ r234c159) b. 12/2 @ r34c1 = {57} (NP @ c1, HW @ r234c159) c. 23/3 @ r678c5 = {689} (NT @ c5, HW @ r678c159) d. 9/3 @ r234c5 = {234} (NT @ c5, HW @ r234c159) e. r2c19 = NP {16} @ r2 f. 7/2 @ r12c9 = {16} (NP @ c9, n3) g. 10/2 @ r67c9 = ...

UA97 V2 is not that hard if you spot the right In/outies: 1. n8 a. Innies @ c5 -> r89c5 = 6 = {15|24} b. Innies @ c6789 -> r89c6 = 15 = {69|78} c. Max r8c56 = {59} = 14; 18/3 -> Min r8c4 = 4 d. Innies @ c1234 -> r89c4 = 12 = [93] | {48|57} e. h6/2 @ r89c5 -> r9c45 <> 6/2 -> r9c6 <> 9 = {678} f. h15/...

Børge wrote:From an extremely reliable source I know that Ruud has paid his provider for the hosting of SudoCue.net until mid December 2008.

If it's the same source that I used, then we know the domain name(s) have been paid, but not necessarilly the hosting (server..) which is a different service.

Let's hope someone posts another puzzle, or variant on Afmob's one, so that Afmob has something to solve. :wink: Preferably only about a 1.5. I joined two cages and here is one rated 1.41 by SS http://img518.imageshack.us/img518/8209/ua97v15qs6.png 3x3::k: 4096:4096:4096:6915:3076:4869:3078:3078:30...

Nasenbaer wrote:Oh, one more thing one or the other might frown upon: you will need uniqueness to place the last numbers.

Uniqueness can be used only for grids with a unique solution which is not the case for this grid since it has 3 solutions. i.e. this grid is invalid.

I usually do not rate puzzles, but I personally did not found it really hard. I would even say it's easy if you're familiar with Kakuro. 1. n8: a. Innies @ c1234 -> r89c4 = 15 = {69|78} b. Innies @ c6789 -> r89c6 = 6 = {15|24} = {4|5..} c. Innies @ c5 -> r89c5 = 9 <> {45} = {18|27|36} d. 13/3 @ r9c4...

Version 1.2b1 released Added support for overlapping variants like samurai, clueless… Added Twin Nonets solver for overlapping variants Added support for bossdoku variant. In design mode, type the letter ‘O’ to change the non-bossanova into bossanova and vice-versa Adapted Conflicting combinations f...

Thanks for the WT, I'll study it. Here are the "tricky" moves which could help simplifying the WT. Indeed I designed both versions around these: For V2: In/Outies @ r5 -> r46c5-r5c19 = 13 Max r46c5 = 17 -> Max r5c19 = 17-13 = 4 Min r5c19 = 3 -> Min r46c5 = 13+3 = 16 -> r46c5 = 16|17 = {9(7...