Assassin 12 - August 18
Posted: Sun Aug 20, 2006 12:10 am
Lots of sums to do on this one. Took a while to find the right "45" for each new part of the puzzle. So good to have SuMoCue to help out! Thanks Ruud.
BTW- I missed not having a lead-in introduction on the puzzle page. The lead-in gives a puzzle more personality. Please keep the lead-in Ruud.
A walkthru follows.
Step 1
“45” on r12 -> 2 outies = 6 -> r3c2=5, r3c8=1 -> r5c9=1
Step 2
r2c23={89}-> no 8 or 9 elsewhere in N1 or r2
-> r4c1 = {89}
-> naked triple on {689} in r4c189 -> no 6, 8 or 9 elsewhere in r4 with 6 locked in N6
-> no 6 elsewhere in N6 or in r3c9 .
Step 3
“45” on r6-9 -> 2 innies = 12
->r6c8=3, r6c4=9, r5c8=2
Step 4
“45” on c12 -> 2 outies = 9
->r2c3=8, r8c3=1, r2c2=9
Step 5
“45” on N7 -> 3 innies = 19
but 2 cannot be in r7c1 since that would require {89} in r79c3
-> r7c1 = 4
-> 2 innies in N7 at r79c3 = 15 = {69} only -> no 6 or 9 elsewhere in N7 or c3
Step 6
r6c12 = {12} -> no 1 or 2 elsewhere in N4
-> 2 in c3 only in N1 -> no 2 elsewhere in N1
-> 10(3) cage in N1 {136} only -> no 1, 3 or 6 elsewhere in N1
-> r34c1= [78]
Step 7
r4c3 = 3 (hidden single c3)
->19(3) cage in N4 = {469} only with r45c2 = [46] and r5c1 =9
-> r5c34 =[58], r67c3=[76], r7c4=3, r9c34=[92], r3c34=[46], r3c9=8, r67c9 =[47]
the rest is mostly singles.
BTW- I missed not having a lead-in introduction on the puzzle page. The lead-in gives a puzzle more personality. Please keep the lead-in Ruud.
A walkthru follows.
Step 1
“45” on r12 -> 2 outies = 6 -> r3c2=5, r3c8=1 -> r5c9=1
Step 2
r2c23={89}-> no 8 or 9 elsewhere in N1 or r2
-> r4c1 = {89}
-> naked triple on {689} in r4c189 -> no 6, 8 or 9 elsewhere in r4 with 6 locked in N6
-> no 6 elsewhere in N6 or in r3c9 .
Step 3
“45” on r6-9 -> 2 innies = 12
->r6c8=3, r6c4=9, r5c8=2
Step 4
“45” on c12 -> 2 outies = 9
->r2c3=8, r8c3=1, r2c2=9
Step 5
“45” on N7 -> 3 innies = 19
but 2 cannot be in r7c1 since that would require {89} in r79c3
-> r7c1 = 4
-> 2 innies in N7 at r79c3 = 15 = {69} only -> no 6 or 9 elsewhere in N7 or c3
Step 6
r6c12 = {12} -> no 1 or 2 elsewhere in N4
-> 2 in c3 only in N1 -> no 2 elsewhere in N1
-> 10(3) cage in N1 {136} only -> no 1, 3 or 6 elsewhere in N1
-> r34c1= [78]
Step 7
r4c3 = 3 (hidden single c3)
->19(3) cage in N4 = {469} only with r45c2 = [46] and r5c1 =9
-> r5c34 =[58], r67c3=[76], r7c4=3, r9c34=[92], r3c34=[46], r3c9=8, r67c9 =[47]
the rest is mostly singles.