Assassin 35

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nd
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Joined: Sun Jun 25, 2006 8:59 am
Location: Toronto

Assassin 35

Post by nd »

Pretty straightforward after the past couple of weeks' puzzles.

Step 1. R56C8 = {16|34} (cannot be {25} as this would block all combos in the 9(3) cage above) => R234C8 = {2(16|34)}. The two cages together block {12346} in the rest of C8 => R8C89 = [52], R179C8 = {789} => R7C78 = [19|37].

Step 2. R8C56 = {79}. R7C56 = {18|36} (can't be {45} because it conflicts with the 6(2) = {15|24} in N8), forming a hidden {13} pair with R7C7 => {13} is eliminated in the rest of R7.

Step 3. 45 rule on N9 => R6C9 + R9C6 = 10 => R67C9 = [54], R9C6 = 5 (only combination no longer blocked!!), R9C45 = {24}.

Step 4. 45 rule on N5 => R46C6 = 12 => R6C67 = [86], R4C6 = 4, R56C8 = {34}, R234C8 = {126}, R45C9 = {78}, R89C9 = [96], R7C78 = [37], R89C7 = {18}, R4C8 = 1, R1C8 = 8, R123C9 = {139}, R1C7 = 5, R45C7 = {29}, R23C7 = [74].

Step 5. 45 rule on C1234 => R469C5 = 9 = [324] (only combo not blocked). R4C4 = 9, R9C4 = 2, , R45C7 = [29], R7C56 = [81], R78C4 = [63], R8C3 = 6, R5C56 = [16], R56C4 = [57].

Step 5. The rest is mop-up. R3C34 = [81] (only place in C4 for the 1 to go), R12C4 = [48], R1C3 = 7, R1C12 = {36}, R2C23 = {14}, R1C56 = [92], R1C9 = 1, R3C56 = [57], R2C56 = [63], R23C8 = [26], R23C9 = [93], R2C1 = 5, R34C1 = [27], R3C2 = 9, R45C9 = [87], R4C23 = [65], R5C2 = 2, and you carry on........
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