Assassin 10

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Caida
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Posts: 38
Joined: Sat Nov 03, 2007 9:24 pm
Location: Canada

Assassin 10

Post by Caida »

Below is my walkthrough for Assassin 10

Now I think all of the Assassins (except for the still "unsolveables") have walkthroughs.

I found this one really easy - I'd rate it 0.75


Assassin 10 walkthrough

Preliminaries

a. 28(4)n1 = {4789/5689} (no 1..3) -> 8,9 locked for n1
b. 5(2)n14 and n58 = {14/23} (no 5..9)
c. 10(3)n3 = {127/136/145/235} (no 8,9)
d. 30(4)n356 = {6789} (no 1..5)
e. 13(2)n36 and n8 = {49/58/67} (no 1..3)
f. 6(2)n58 = {15/24} (no 3, 6..9)
g. 14(4)n6 = {1238/1247/1256/1346/2345} (no 9)
h. 9(3)n7 = {126/135/234} (no 7..9)
i. 6(3)n9 = {123} -> 1,2,3 locked for n9

1. Innies n1: r3c13 = 7(2) = [16/25]/{34}
1a. -> r3c3 no 1,2,7

2. Innies n3: r3c79 = 12(2) = [75/84]
2a. -> r3c7 no 6,9
2b. -> r3c9 no 6,7,8,9
2c. -> r4c9 no 4,5,6,7
2d. -> r4c45 no 6,9 (CPE with 30(4)n356))

3. Innies n7: r7c23+r8c3 = 19(3) = {289/379/469/478/568} (no 1)

4. Innies n9: r7c78+r8c7 = 22(3) = {589/679}
4a. r7c78+r8c7 no 4
4b. 9 locked for n9 in r7c78+r8c7 -> no 9 elsewhere in n9
4c. 4 locked for n9 in r9 -> no 4 elsewhere in r9
4d. r8c5 no 9

5. Innies c1234: r123c4 = 21(3) = {489/579/678} (no 1,2,3)

6. Innies c6789: r123c6 = 16(3)
6a. -> r123c5 = 8(3) = {125/134} (no 6,7,8,9)
6b. -> 1 locked in c5 and n2

7. Innie c5: r4c5 = 8 (using step 6a for r123c5)
7a. r4c9 = 9
7b. r3c9 = 4
7c. r3c7 = 8 (step 2)
7d. r5c6 = 9 (hidden single within 30(4))
7e. pair {67} locked for r4 in r4c67
7f. r3c13 no 3 (step 1)
7g. r4c1 no 1,2
7h. r89c5 no 5
7i. r7c8 no 5 (step 4)

8. 28(4)n1 = {4789} -> locked for n1
Note: {5689} blocked by r3c3

9. Innie and Outie n6: r4c7 = r7c8
9a. -> r7c8 no 8,9
9b. -> r7c78+r8c7 = {679} (step 4)
9c. -> 17(3)n9 = {458} -> locked for n9 and r9

10. 23(4)n89
10a. -> r78c7 = {69/79}
10b. -> r89c6 = 8(2)/7(2) -> no 8
10c. -> single: r8c4 = 8
10d. -> r7c2 = 8

11. 17(3)n7 = {179/269}
11a. -> r9c123 no 3
11b. -> 9 locked in r9c123 for n7 and r9
11c. single: r7c5 = 9
11d. -> r8c7 = 9
11e. -> 13(2)n8 = {67} -> locked for n8 and c5

12. Innies n7 (step 3): r78c3 = 11(2) = {47/56} (no 2,3)
12a. -> r9c4 = 1
12b. 5(2)n58 = {23} -> locked for c4
12c. single: r6c6 = 1
12d. r7c6 = 5
12e. r7c6 = 4
12f. r7c7 = 7; r9c6 = 3 (cage sum)

Singles and cage sums are all that is left
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