Assassin 89
Posted: Fri Feb 08, 2008 4:08 am
Woo Hoo! Gotta love that Central Time Zone! I don't rate puzzles with a number scale, but put this one down as disturbingly easy. Is this really Ruud's site?
Afmob tells me that the sign error in Step 20 requires all subsequent steps to be re-done. I don't have time for that, so keep it in mind if you are using this walkthru. My apologies.
Editted once to correct sign error (thanks Afmob!) and to add lines for readability.Prelims:
a) N1: 11(2) no 1
b) N14: 19(3) no 1
c) N2: 14(4) no 9
d) N23: 21(3) no 1,2,3
e) N23: 13(2) no 1,2,3
f) N3: 11(3) no 9
g) N4:10(3) no 8,9
h) N4: 20(3) no 1,2
i) N69: 22(3) no 1,2,3,4
j) N78: 7(2) no 7,8,9
k) N78: 19(2) no 1
l) N89: 10(3) no 8,9
m) N9: 9(2) no 9
Assumption: I assume Row, Column, Nonet and/or Cage cleanups after each step that results in any locked or placed digits. Other cleanups are noted as sub-steps.
Solving:
1) N69: 22(3): 9 locked in cage and C7
a) R1C6 no 4
2) N14: 1 innie : R2C3 = 1
a) R23C4 no 2,3
3) N69: 1 innie: R8C7 = 3
a) R78C6 no 4,7
4) N3: 2 outies: R23C6 = 17  R23C6 = {89} locked for N2, C6
a) R3C7 no 6,7,8
b) R23C4 = {67} locked for N2, C4
5) N2: 14(4) combo analysis: no 1
a) R3C5 = 1
6) N3: 9 locked in 17(3)  no 4,7,8
7) N3: 1 locked in R1C89 of 11(3)  no 5 in 11(3)
8) N7: 2 outies: R78C4 = 13  R7C4 no 1,2,3; R8C4 no 2,4,5
a) R7C3 no 4,5,6
9) C6789: 2 innies: R19C6 = 9  R9C6 no 1,2,3
10) C1234: 2 innies: R19C4 = 5  R1C4 no 5; R9C4 no 4,5,8,9
11) C89: 2 outies: R49C7 = 3  R49C7 = {12}
a) R9C8 no 1,2,4,5,6
b) N6: 16(3) combo analysis: R4C89 no 1,2,3,4
12) C7: 4 locked into R123C7 for C7 and N3
a) N3: 11(3) no 6
13) C12: 2 outies: R16C3 = 12  R1C3 no 2,6; R6C3 no 6
a) R2C1 no 5,9
14) N5: 1 outie: R7C5 = 7
15) C6: 7 locked in R456C7  12(3) no 5,6
16) N8: 3 locked in R9C45 for N8, R9
17) R1: 9 locked in R1C13 for N1, R1
18) N1: 1 innie and 1 outie: R3C3 = R4C2 +4 R4C2 no 5,6,7,8,9; R3C3 no 2,3,4
19) N9: 1 innie and 1 outie: R7C7 = R6C8 + 6  R6C8 no1,4,5,6,7,8,9; R7C7 no 5,6
20) C9: 2 innies and 2 outies: R34C9 - 7 = R15C8
a) Max R15C8 = 17  max R34C9 = 10  R4C9 no 9, R3C9 no 6,9
21) C8: 9 locked into R23C8 for 17(3) cage, N3 and C8
a) R23C8 no 2
22) N6: 16(3) combo analysis: {[1]78/[2]68}  R4C89 no 5 and 8 locked into R4C89 for 16(3) cage, N6, R4
23) R1: 2 innies and 2 outies: R1C17 = R2C59 + 9
a) Max R1C17 = 17  max R2C59 = 8  R2C9 no 7,8
b) Min R2C59 = 5  min R1C17 = 14  R1C1 no 2,3,4,5; R1C7 no 4
24) N3: 11(3) combo analysis: R1C89 no 2,3
25) C9: 2 locked in R23C9 for C9
26) N6: 4 locked into 13(3) cage  no 1,5,9 in 13(3) cage.
27) N6: 5 locked into R56C7 and step 1  22(3) = {589}
a) R7C7 = 8, R56C7 = {59} locked for C7
b) R3C7 = 4 NS  R3C6 = 9
c) R2C6 = 8
28) N9: NS R9C8 = 7  R9C7 = 2
a) R4C7 = 1
29) N6: 16(3) combo analysis: R4C9 = 7 and R4C8 = 8
30) N3: R1C8 = 1 NS  R1C9 = 8 R2C9 = 2
31) N3: 17(3) Combo analysis: R23C8 no 6  R3C89 = {35} locked for N3, R3  R2C8 = 9 NS
32) N1: 11(2) Combo analysis: R1C23 no 3
33) N2: 3 locked into R1C456  R2C5 no 3
34) R2: {67} NP at R2C47 locked for R2
35) N2: 2 locked in R1C456 for R1  R1C3 no 9
36) N1: R1C1 = 9 HS  15(3) combo analysis: R2C1 = 4; R3C1 = 2
37) N2: R2C5 = 5 NS
38) N1: R1C3 = 5 NS  R1C2 = 6
39) N1: R2C2 = 3 NS  14(3) Combo Analysis: R3C2 = 7, R4C2 = 4
40) Cleanup Naked Singles: R3C3 = 8, R3C4 = 6, R2C4 = 7, R12C7 = [76]
41) N4: 1 locked into R5C12 for 10(3), R5
a) 10(3) no 5
b) N4: 5 locked into R6C12 for 20(3) and R6
c) 20(3) no 3
d) R6C7 = 9 NS
e) R5C7 = 5 NS
f) R6C3 = 7 NS
g) R6C1 no 6  R6C12 ={58} locked for R6
42) N5: R4C4 = 5 HS
a) R7C4 = 4 NS  R7C3 = 3
43) N5: 6 locked into R456C5 for 27(5) N5 and C5
44) Cleanup Hidden Singles: R9C1 = 7, R5C6 = 7
45) N14: 19(3) R45C3 = {29} locked for N4 and C3
46) N5: R5C2 = 1 NS  R45C1 = {36} locked for C1
47) N78: 19(3) has R89C3 = {46} locked  R8C4 = 9
48) C4: R5C4 = 8 HS
49) Rest of puzzle is a cascade of Naked Singles.
965234718
431758692
278619435
349562187
612897543
857143926
523471869
784926351
196385274
Afmob tells me that the sign error in Step 20 requires all subsequent steps to be re-done. I don't have time for that, so keep it in mind if you are using this walkthru. My apologies.
Editted once to correct sign error (thanks Afmob!) and to add lines for readability.Prelims:
a) N1: 11(2) no 1
b) N14: 19(3) no 1
c) N2: 14(4) no 9
d) N23: 21(3) no 1,2,3
e) N23: 13(2) no 1,2,3
f) N3: 11(3) no 9
g) N4:10(3) no 8,9
h) N4: 20(3) no 1,2
i) N69: 22(3) no 1,2,3,4
j) N78: 7(2) no 7,8,9
k) N78: 19(2) no 1
l) N89: 10(3) no 8,9
m) N9: 9(2) no 9
Assumption: I assume Row, Column, Nonet and/or Cage cleanups after each step that results in any locked or placed digits. Other cleanups are noted as sub-steps.
Solving:
1) N69: 22(3): 9 locked in cage and C7
a) R1C6 no 4
2) N14: 1 innie : R2C3 = 1
a) R23C4 no 2,3
3) N69: 1 innie: R8C7 = 3
a) R78C6 no 4,7
4) N3: 2 outies: R23C6 = 17  R23C6 = {89} locked for N2, C6
a) R3C7 no 6,7,8
b) R23C4 = {67} locked for N2, C4
5) N2: 14(4) combo analysis: no 1
a) R3C5 = 1
6) N3: 9 locked in 17(3)  no 4,7,8
7) N3: 1 locked in R1C89 of 11(3)  no 5 in 11(3)
8) N7: 2 outies: R78C4 = 13  R7C4 no 1,2,3; R8C4 no 2,4,5
a) R7C3 no 4,5,6
9) C6789: 2 innies: R19C6 = 9  R9C6 no 1,2,3
10) C1234: 2 innies: R19C4 = 5  R1C4 no 5; R9C4 no 4,5,8,9
11) C89: 2 outies: R49C7 = 3  R49C7 = {12}
a) R9C8 no 1,2,4,5,6
b) N6: 16(3) combo analysis: R4C89 no 1,2,3,4
12) C7: 4 locked into R123C7 for C7 and N3
a) N3: 11(3) no 6
13) C12: 2 outies: R16C3 = 12  R1C3 no 2,6; R6C3 no 6
a) R2C1 no 5,9
14) N5: 1 outie: R7C5 = 7
15) C6: 7 locked in R456C7  12(3) no 5,6
16) N8: 3 locked in R9C45 for N8, R9
17) R1: 9 locked in R1C13 for N1, R1
18) N1: 1 innie and 1 outie: R3C3 = R4C2 +4 R4C2 no 5,6,7,8,9; R3C3 no 2,3,4
19) N9: 1 innie and 1 outie: R7C7 = R6C8 + 6  R6C8 no1,4,5,6,7,8,9; R7C7 no 5,6
20) C9: 2 innies and 2 outies: R34C9 - 7 = R15C8
a) Max R15C8 = 17  max R34C9 = 10  R4C9 no 9, R3C9 no 6,9
21) C8: 9 locked into R23C8 for 17(3) cage, N3 and C8
a) R23C8 no 2
22) N6: 16(3) combo analysis: {[1]78/[2]68}  R4C89 no 5 and 8 locked into R4C89 for 16(3) cage, N6, R4
23) R1: 2 innies and 2 outies: R1C17 = R2C59 + 9
a) Max R1C17 = 17  max R2C59 = 8  R2C9 no 7,8
b) Min R2C59 = 5  min R1C17 = 14  R1C1 no 2,3,4,5; R1C7 no 4
24) N3: 11(3) combo analysis: R1C89 no 2,3
25) C9: 2 locked in R23C9 for C9
26) N6: 4 locked into 13(3) cage  no 1,5,9 in 13(3) cage.
27) N6: 5 locked into R56C7 and step 1  22(3) = {589}
a) R7C7 = 8, R56C7 = {59} locked for C7
b) R3C7 = 4 NS  R3C6 = 9
c) R2C6 = 8
28) N9: NS R9C8 = 7  R9C7 = 2
a) R4C7 = 1
29) N6: 16(3) combo analysis: R4C9 = 7 and R4C8 = 8
30) N3: R1C8 = 1 NS  R1C9 = 8 R2C9 = 2
31) N3: 17(3) Combo analysis: R23C8 no 6  R3C89 = {35} locked for N3, R3  R2C8 = 9 NS
32) N1: 11(2) Combo analysis: R1C23 no 3
33) N2: 3 locked into R1C456  R2C5 no 3
34) R2: {67} NP at R2C47 locked for R2
35) N2: 2 locked in R1C456 for R1  R1C3 no 9
36) N1: R1C1 = 9 HS  15(3) combo analysis: R2C1 = 4; R3C1 = 2
37) N2: R2C5 = 5 NS
38) N1: R1C3 = 5 NS  R1C2 = 6
39) N1: R2C2 = 3 NS  14(3) Combo Analysis: R3C2 = 7, R4C2 = 4
40) Cleanup Naked Singles: R3C3 = 8, R3C4 = 6, R2C4 = 7, R12C7 = [76]
41) N4: 1 locked into R5C12 for 10(3), R5
a) 10(3) no 5
b) N4: 5 locked into R6C12 for 20(3) and R6
c) 20(3) no 3
d) R6C7 = 9 NS
e) R5C7 = 5 NS
f) R6C3 = 7 NS
g) R6C1 no 6  R6C12 ={58} locked for R6
42) N5: R4C4 = 5 HS
a) R7C4 = 4 NS  R7C3 = 3
43) N5: 6 locked into R456C5 for 27(5) N5 and C5
44) Cleanup Hidden Singles: R9C1 = 7, R5C6 = 7
45) N14: 19(3) R45C3 = {29} locked for N4 and C3
46) N5: R5C2 = 1 NS  R45C1 = {36} locked for C1
47) N78: 19(3) has R89C3 = {46} locked  R8C4 = 9
48) C4: R5C4 = 8 HS
49) Rest of puzzle is a cascade of Naked Singles.
965234718
431758692
278619435
349562187
612897543
857143926
523471869
784926351
196385274