Code: Select all
.------------------.------------------.------------------.
| 8 46 369 | 7 2 13 | 5 1469 349 |
| 7 1 23569| 359 359 4 | 2389 268 239 |
| 345 245 2359 | 6 1359 8 | 239 1249 7 |
:------------------+------------------+------------------:
| 125 9 16 | 58 158 136 | 4 7 235 |
| 1245 456 7 | 359 13459 136 | 239 259 8 |
| 45 3 8 | 2 4579 79 | 1 59 6 |
:------------------+------------------+------------------:
| 13 25 13 | 4 6 79 | 2789 289 259 |
| 6 8 24 | 1 79 5 | 279 3 249 |
| 9 7 45 | 38 38 2 | 6 45 1 |
'------------------'------------------'------------------'
Code: Select all
.------------------.------------------.------------------.
| 8 #4*6 369 | 7 2 13 | 5 1469 3!49 |
| 7 1 23569| 359 359 4 | 2389 268 239 |
| #345 245 2359 | 6 1359 8 | 239 1249 7 |
:------------------+------------------+------------------:
| 125 9 #1*6 | 58 158 13#6 | 4 7 2$3!5|
| 1245 45#6 7 | 359 13459 13*6 | 2@39 259 8 |
| 45 3 8 | 2 4579 79 | 1 59 6 |
:------------------+------------------+------------------:
| #1*3 25 *1#3 | 4 6 79 | 2789 289 259 |
| 6 8 24 | 1 79 5 | 279 3 249 |
| 9 7 45 | 38 38 2 | 6 45 1 |
'------------------'------------------'------------------'
I could make a conflict with a third cluster though: (4)r1c2 - (4)r1c9=(4)r8c9=(4=5)r9c8=(5)r7c9=(5)r4c9 - (3)r4c9 (I wrote the 2 weak links making the bridges also to the ends of this chain -- (4)r1c2 also belongs to the big first chain with the same color as (6)r4c6). Is this the Medusa SudoCue suggests (maybe, as SudoCue shows two yellow cells as well: (4)r1c9 and (5)r4c9 shown with ! above) or is there a simpler bridge?
I can see a little bit simpler pattern making the same elimination: If r1c3 couldn't be 3 then r1c69 with box 6 would be an [[Empty_Rectangle|Empty Rectangle]] on candidate 3 eliminating r5c6. Now if r1c3==3 then there is a short chain: r7c3==1 => r4c3==6 => r4c6<>6 => r5c6==6, so (3)r5c6 can be removed.
Well, this combination of an ER and a 3D Chain is not easy to spot but probably easier than 3 bridged clusters. But of course they are not equivalent...
Istvan