Post
by Afmob » Sat Apr 19, 2008 12:34 pm
Like in WK 3 is used the Innies and Outies of the Windows to crack it.
WK 4 Walkthrough:
1. R6789
a) 24(3) = {789} locked for R9+N8
b) Innies N7 = 23(3) = {689} locked for N7
c) 12(3) = {345} locked for R9+N7
d) 9(3) = {126} locked for N9
e) 20(3) = 9{38/56} -> 9 locked for C3+N7 + R678C234 and R8C4 = (35)
f) Innies+Outies N9: -1 = R8C6 - R7C8 -> R8C6 = (234)
g) 21(3) = 9{48/57} -> 9 locked for N9
h) Innies R678C234 = R678C2 = 11(3): R68C2 <> 5,6,7,8,9 because R7C2 = (68)
i) 10(3) = {127} -> 7 locked for C1 + R678C159
j) 7 locked in Outies R678C234 = R678C1 = 12(3) = 7{14/23} -> R6C1 = (34)
2. C6789
a) Innies R678C678 = R678C8 = 12(3) <> 9 because R7C8 >= 3
b) 21(3) = 9{48/57} -> 9 locked for C9 + R678C159
c) 31(5) = 9{1678/2578/3478/3568/4567} -> 9 locked for C8
d) Outies C89 = 9(3) <> 7,8,9
e) 9(3) @ N9 <> 6 because R7C8 <> 1,2,6
3. R6789
a) 6 in R678C159 locked in 15(3) @ R6C5 for C5 -> 15(3) = 6{18/45}
b) Killer pair (68) locked in 20(3) + R7C2 for R678C234
c) 14(3) @ N7 = 7{25/34} -> 7 locked for R6
d) 16(3) must have 1 since together with 10(3) it's only possible there @ R78
e) 16(3) = {168} -> R6C5 = 8 (locked for R678C159); {16} locked for C5+N8 + R678C159
f) Naked pair (27) locked R78C1 for C1+N7 + R678C159
g) Outies R678C234 = R678C1 = 12(3) = {237} -> R6C1 = 3 (locked for R678C234)
h) 19(3) = {469} -> R7C6 = 4 (locked for R678C678)
i) 14(3) @ N9 = {257} -> R8C6 = 2 (locked for R678C678), R78C7 = {57} locked for C7+N9
j) R7C9 = 9, R8C9 = 4, R6C9 = 5, R7C8 = 3 -> R6C8 = 1
4. C1234
a) 14(3) = {257} -> R7C4 = 5, {27} locked for R6
b) R6C2 = 4 -> R7C2 = 6
c) 16(4) = {1258} locked for N4 because R6C3 = (27) blocks {1267}
d) R6C3 = 7, R4C2 = 9 (locked for R234C234), R4C1 = 6 (locked for R234C159)
e) 26(4) = {3689} -> {38} locked for C2+N1 + R234C234
f) Hidden Single: R1C2 = 7 @ N1 (locked for R159C234)
g) 18(3) = {189/369/459/468} <> 2
h) Hidden Single: R3C3 = 2 @ N1 (locked for R234C234)
i) 15(3) = {267} -> {67} locked for C4+N2 + R234C234
5. N23
a) 15(3) @ R1C5 = {249} locked for C5+N2
b) 18(3) = {468} -> R1C4 = 8 (locked for R159C234), R2C3 = 4 (locked for R234C234),
R1C3 = 6 (locked for R159C234)
c) 9(3) = 3{15/24} -> 3 locked for C9+N3; R1C8 = (45)
d) 9 locked in R23C8 for N3
e) 12(3) @ R1 = 1{38/56} because R1C6 <> 2,4,6 and R1C8 = (45) blocks {345}
-> R1C7 = 1 (locked for R159C678)
6. Rest is singles with considering the windows.