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Assassin 76
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CathyW
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PostPosted: Fri Nov 09, 2007 12:04 pm    Post subject: Assassin 76 Reply with quote

Getting in first again Very Happy

Will be checking my WT later and then posting it but for now key moves include innies of N9, a couple of conflicting combinations and killer pairs. Rating of 1.00 imho.
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Para
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PostPosted: Fri Nov 09, 2007 1:51 pm    Post subject: Reply with quote

Hi all

With Cathy's reassurance that it was only a rating 1.00, i thought i'd send in my First V1 walk-through since ages. And it proved to be a quickie. Took me about 40 minutes to solve with keeping the walk-through. A rating of 1.00 sounds about right. Not anything spectacular.

Walk-through Assassin 76

1. R1C12 = {18/27/36/45}: no 9

2. R1C89 = {16/25/34}: no 7,8,9

3. 19(3) at R2C8 = {289/379/469/478/568}: no 1

4. 9(3) at R6C8 = {126/135/234}: no 7,8,9

5. 20(3) at R7C4 and R8C8 = {389/479/569/578}: no 1,2

6. R89C1 = {15/24}: no 3,6,7,8,9

7. R89C9 = {69/78}: no 1,2,3,4,5

7.5 14(4) at R2C9 = {1238/1247/1256/1346/2345}: no 9

8. 45 on N9: 4 innies: R7C789 + R8C7 = 10 = {1234} -> locked for N9

9. 45 on C89: 2 outies: R39C7 = 10 = [28/37/46]: R3C7: no 5,6,7,8,9; R9C7: no 5,9
9a. 5 in N9 locked for C8
9b. Clean up: R1C9: no 2

10. 45 on C89: 4 innies: R2389C8 = 29 = {5789} -> locked for C8

11. 45 on C12: 2 outies: R39C3 = 8 = {17/26/35}: no 4,8,9

12. 45 on R1234: 2 innies: R4C37 = 15 = {69/78}: no 1,2,3,4,5

13. 45 on N2: 2 innies: R1C46 = 13 = {49/58/67}: no 1,2,3

14. 45 on N5: 2 innies: R5C46 = 6 = {15/24}: no 3,6,7,8,9
14a. Cage overlap: R5C67 can't total 6: R4C7: no 7
14b. Clean up: R4C3: no 8

15. 13(3) at R4C7 = [643]/[6]{25}/[823]/[8]{14}/[913]: R5C7: no 6,7,8,9

16. 17(3) at R4C3 = [692/674/791/782/764/971/962/935]: R5C3: no 1,2,4,5

17. 45 on N8: 2 innies: R8C46 = 8 = {17/26/35}: no 4,8,9

18. 45 on R1234: 2 outies: R5C37 = 9 = [81/72/63]
18a. Clean up: R5C4: no 5(step 16); R5C6: no 1

19. 13(3) at R4C7 = [643/652/823/841]: no 9
19a. Clean up: R4C3: no 6

20. 45 on R89: 2 innies: R8C37 = 7 = [34/43/52/61]: R8C3: no 1,2,7,8,9

21. 45 on C789: 3 outies: R158C6 = [821/641/542/425/452]: R1C6: no 7,9; R8C6: no 3,6,7
21a. Translation through 45's N2,5 and 8: R158C4 = [547/826/943/916]: R1C4 = {589}, R8C4 = {367}
21b. Clean up: R1C6: no 6

22. Naked Quad {1234} in R3578C7 -> locked for C7 (Really should have seen this after step 18)

23. 17(3) at R1C6 = [4]{58/67}: R1C6 = 4; R12C7: no 9
23a. R1C4 = 9; R6C7 = 9(hidden)
23b. Clean up: R5C4: no 2; R8C4: no 7(step 21); R8C6: no 1
23c. Naked Pair {25} in R58C6 -> locked for C6

24. 16(4) at r6C7 = 9{14}[2](last combo): R8C6 = 2; R78C7 = {14} -> locked for C7 and N9
24a. R8C4 = 6; R5C46 = [15]

Now it is very basic, so won't clean up properly anymore. Just showing the final combinations that will get you to all singles.

25. R8C37 = [34](last combo from step 20)
25a. R7C7 = 1

26. R45C7 = [62] (last combo within 13(3) at R4C7)
26a. R3C7 = 3; R9C7 = 7; R4C3 = 9; R5C3 = 7; R5C5 = 9(hidden)

27. R89C9 = [96](last combo)
27a. R1C8 = 6(hidden); R1C9 = 1;
27b. R7C8 = 2(hidden); R7C9 = 3; R456C8 = [134]; R456C9 = [785]

28. R67C3 = [84](last combo within 21(4) at R6C3)

29. R12C3 = [51](last combo within 15(3) at R1C3)
29a. R12C7 = [85]; R9C3 = 2; R3C3 = 6

30. R23C2 = [34](last combo within 13(3) at R2C2)

And the rest is hidden and naked singles till the end.

greetings

Para


Last edited by Para on Mon Nov 19, 2007 11:17 pm; edited 2 times in total
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mhparker
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PostPosted: Fri Nov 09, 2007 2:51 pm    Post subject: Reply with quote

Hi Cathy,

CathyW wrote:
Getting in first again Very Happy

Indeed, I just took a look, and can proudly announce that you've just moved up into joint first place with Andrew, as shown below (Assassin numbers in brackets). No prizes for guessing who's bottom of the pile Wink:

Quote:
Assassin Thread Openers "League Table":

1. Andrew 11 (13,14,15,17,19,28,30,34,40,66,73)
1. CathyW 11 (47,49,54,55,56,59,61,65,69,71,76)
3. sudokuEd 9 (3,4,6,8,9,12,16,26,36)
4. nd 7 (7,11,22,23,27,29,35)
5. Nasenbaer 5 (20,21,31,32,38)
5. Para 5 (37,39,44,48,62)
5. Ruud 5 (24,42,50,52,53)
8. frank 3 (45,68,72)
8. Jean-Christophe 3 (51,57,58)
8. rcbroughton 3 (33,43,60)
11. goooders 2 (63,64)
11. PsyMar 2 (25,41)
11. sublue 2 (74,75)
14. Afmob 1 (70)
14. annette 1 (18)
14. Howard S 1 (67)
14. mhparker 1 (46)


Note: The following Assassins appear to have no forum thread: 1, 2, 5, 10, 24 (there's one for "A24 - Tetris", but I missed the one for the A24 original)

Edit: Updated table due to info from Para (see post below) re: A24 Tetris being the original A24. Thanks. Unfortunately it doesn't help: I'm still in the "relegation zone"... Sad
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Mike


Last edited by mhparker on Fri Nov 09, 2007 4:27 pm; edited 1 time in total
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Afmob
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PostPosted: Fri Nov 09, 2007 3:07 pm    Post subject: Reply with quote

This one wasn't too difficult but I needed one little trick to crack it open (step 9c).

A76 Walkthrough:

1. N258
a) Innies N2 = 13(2) = {49/58/67}
b) Innies N5 = 6(2) = {15/24}
c) Innies N8 = 8(2) = {17/26/35}

2. N9
a) Killer pairs (79,89) of 15(2) block {389/479} of 20(3)
b) 20(3) = 5{69/78} -> 5 locked
c) Hidden Quad (1234) in R7C789+R8C7 -> no other candidates
d) 9(3): R6C8 <> 1 since R7C89 <= 7
e) 16(4): R6C7 <> 1 since R7C7+R8C67 <= 14

3.C789
a) Outies C9 = 16(5) = {12346} locked for C8
b) Outies C89 = 10(2) = [28/37/46]
c) Outies C789 = 11(3) -> no 9
d) Outies C789 = 11(3): R8C6 <> 7 because R15C6 >= 5
e) 19(3) = {289/379/478}
f) 7(2): R1C9 <> 2

4. C123
a) Outies C12 = 8(2) = {17/26/35}
b) Outies C123 = 16(3): R8C4 <> 1 since R15C4 <= 14
c) 17(3) @ N4: R45C3 <> 1,2 because R5C4 <= 5

5. N2
a) Innies N2 = 13(2): R1C4 <> 4

6. R6789
a) Innies+Outies: 2 = R5C5 - R6C19
-> R5C5 must be at least 5 since R6C19 >= 3 -> R5C5 = (56789)
-> R6C19 = 3/4/5/6/7 -> R6C19 <> 7,8,9
b) 16(3) @ N6 must have 7,8 or 9 and they're only possible @ R5C9 -> R5C9 = (789)

7. R1234
a) Innies = 15(2) = {69/78}
b) 13(3) @ R4 must have 6,7,8 xor 9 and R4C7 = (6789) -> R5C7 <> 6,7,8,9
c) Outies = 15(4) must have 6,7,8 xor 9 - only possible @ R5C3 -> R5C3 = (6789)
d) 17(3) @ N5: R5C4 <> 5 because R45C3 >= 13

8. N258
a) Outies C123 = 16(3): R8C4 <> 2 since R15C4 <= 13
b) Innies N5 = 6(2): R5C6 <> 1
c) Innies N8 = 8(2): R8C6 <> 6
d) 13(3) @ N5 <> 9 because R5C6 <> 1,3,9
e) 13(3) @ N5 <> 7 because R5C78 would be {15/24} -> no combo for Innies N5
f) 16(4): R6C7 <> 5 since R7C7+R8C67 would be <= 9

9. N456 !
a) 12(3): R5C2 <> 9 because R56C1 would be {12} -> blocked by Killer pair (12) of 6(2)
b) Innies R1234 = 15(2): R4C3 <> 6,8
c) ! Outies R1234 = 15(4) contains Innies N5 = 6(2) -> R5C37 = 9(2) = [63/72/81]
d) 5 locked in R46C9 for C9

10. N123
a) 7(2) = {16/34}
b) 5 locked in 17(3) @ C3 = 5{39/48}; R1C6 <> 5
c) 17(3) = {458} since R1C6 = (48); R1C89 <> 4
d) 7(2) = {16} locked for R1+N3
e) 9(2) = {27/45}
f) Innies N2 = 13(2) = [58/94]
g) Killer pair (45) of Innies N2 blocks {45} of 9(2)
h) 9(2) = {27} locked for R1+N1
i) 13(3) @ N1 = {139/148/346}
j) Hidden Single: R6C7 = 9 @ C7, R9C7 = 7 @ C7, R4C7 = 6 @ C7, R1C8 = 6 @ C8 -> R1C9 = 1

11. N9
a) 20(3) = {578} locked, 8 locked for C8
b) 16(4) = {1249}, 4 locked for C7+N9
c) 9(3) = {234} -> R6C8 = 4; {23} locked for C7+N9
d) 16(4) = {1249} -> R8C6 = 2

12. N8
a) Innies = 8(2) = [62] -> R8C4 = 6
b) 20(3) = 7{49/58} -> 7 locked for R7+N8

13. N23
a) 19(3) = {379} -> R3C7 = 3
b) 17(3) = {458} -> R1C6 = 4; {58} locked for N3
c) Innies N2 = 13(2) = [94] -> R1C4 = 9
d) 15(3) = {159} -> R1C3 = 5, R2C3 = 1
e) 19(4) = {2368} locked for N2
f) 13(3) = {157} locked for R3

14. N1
a) 13(3) = {346} -> R2C2 = 3, R3C2 = 4, R3C3 = 6
b) 25(4) = 89{17/35} -> R4C12 = {17/35}; R4C1 <> 5; {89} locked for C1 ^

15. N56
a) Innies N5 = 6(2) = [15] -> R5C6 = 5, R5C4 = 1
b) 13(3) = [652] -> R5C7 = 2
c) 16(3) = [385] -> R5C8 = 3, R5C9 = 8, R6C9 = 5

16. N47
a) 4 locked in 21(4) = 46{29/38} for N7
b) 6(2) = {15} locked for C1+N7
c) 16(3) = 6[19/28] -> R7C1 = 6
d) 12(3) = 2{37/46} -> R6C1 = 2
e) 16(3) = {169} -> R6C2 = 1, R7C2 = 9

17. Rest is singles.

Rating: 1.0 since it was quite straightforward apart from the little trick.


Last edited by Afmob on Sun Nov 18, 2007 10:40 am; edited 2 times in total
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Para
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PostPosted: Fri Nov 09, 2007 3:52 pm    Post subject: Reply with quote

Hi

A24-Tetris is of the original puzzle. I think the addition Tetris is from Ruud's description in referring to the Tetris game because of the many tetromino shaped cages in the puzzle.

Para

ps. Cathy does have the notion of writing the first message without a WT just after her lunch break Wink
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CathyW
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PostPosted: Fri Nov 09, 2007 5:02 pm    Post subject: Reply with quote

Laughing I've been rumbled!

Just got home and have to go cook dinner shortly but I will be posting my WT later on.

I'm sure some of the 'new kids on the block' will be catching me up very soon with the first posts. Welcome to you all. Smile

Cathy x
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gary w
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PostPosted: Fri Nov 09, 2007 7:54 pm    Post subject: 76 Reply with quote

Wow..so many wts already.Really nothing to add other than I'ld agree as far as I'm competent to judge that this one is about a 1.0.Didn't take too long to do..but about 4 times longer than today's Times "deadly" killer.
Ruud's puzzles still set the bench mark.

Regards

Gary

P.S. Have had a look at the jigsaw killer no.32.No wonder noone has posted a wt!!whew...anyone thinking of starting a tag.??
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CathyW
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PostPosted: Fri Nov 09, 2007 9:18 pm    Post subject: Reply with quote

As promised:

Prelims

a) 9(2) N1 = {18/27/36/45}
b) 7(2) N3 = {16/25/34}
c) 9(3) N6/9 = {126/135/234}
d) 20(3) N8 = {389/479/569/578}
e) 6(2) N7 = {15/24}
f) 20(3) N9 = {389/479/569/578}
g) 15(2) N9 = {69/78}


1. Innies N9: r7c789 + r8c7 = 10 = {1234}
a) -> 20(3) = {569/578}

2. Innies N2: r1c46 = 13 = {49/58/67}

3. Innies N5: r5c46 = 6 = {15/24}

4. Innies N8: r8c46 = 8 = {17/26/35}

5. Outies c12: r39c3 = 8 = {17/26/35}

6. Outies c89: r39c7 = 10 = [28/37/46]
a) -> 5 locked r89c8 n/e c8 -> r1c9 <> 2

7. Innies r1234: r4c37 = 15 = {69/78}
a) -> r5c37 = 9 = {18/27/36} ({45} blocked by split 6(2) r5c46)

8. Outies c123: r158c4 = 16 = [457/547/745/817/826/853/916/925/952/943]
a) -> r1c4 <> 6 -> r1c6 <> 7
b) -> r8c4 <> 1 -> r8c6 <> 7

9. Outies c789: r158c6 = 11 -> r1c6 <> 9 -> r1c4 <> 4

10. Innies r89: r8c37 = 7 = [34/43/52/61]

11. Innies r1: r1c357 = 16

12. Outies N1: r1c4 + r4c12 = 17

13. Outies N3: r1c6 + r4c89 = 12 = 4{17/26}/[35], 5{16/34}/[25], 6[15]/{24}, 8{13}
a) -> r4c89 <> 8

14. Outies N7: r6c23 + r8c4 = 15

15. Outies N9: r6c78 + r8c6 = 15
a) Max from r6c8 + r8c6 = 6+6 = 12 -> r6c7 = min 3

16. 9(3) @ r6c8 = {126/234} -> r6c8 <> 1

17. r56c1 of 12(3) canít be {12} as would conflict with 6(2) r89c1 -> r5c2 <> 9

18. 13(3) @ r4c7 = [652/643/742/751/841/823/913]
a) r5c7 = (123) -> r5c3 = (678)
b) NQ {1234} r3578c7 -> r126c7 <> 1,2,3,4
c) 17(3) @ r1c6 = [458/485/467/476] -> r1c6 = 4 -> r1c4 = 9
d) Clean up: r1c12 <> 5, r12c3 = [15/24/51], r1c89 <> 3, r5c4 <> 2, r8c6 <> 3 -> r8c4 <> 5

19. 9 locked r23c8 n/e c8
a) 20(3) N9 = {578}, 15(2) N9 = {69} n/e c9 -> r1c8 <> 1
b) Clean up: r3c7 <> 4

20. 19(3) N3 = {289/379} -> r23c8 = {789)
a) NQ {5789} r2389c8 -> r4c8 <> 7, r5c8 <> 7,8
Note: could have got this earlier from innies of c89!

21. Conflicting combo: 9(2) r1c12 <> {18} as would force 7(2) r1c89 = [25] then no candidates left in r1c3!

22. Killer pair {26} in r1c12 + r1c8 -> r1c357 <> 2,6
a) -> r12c3 = {15} n/e N1/c3
b) -> r39c3 = {26} only remaining combo n/e c3
c) -> split 7(2) r8c37 = {34} n/e r8
d) -> split 8(2) r8c46 = {26} n/e r8
e) -> r8c9 = 9, r9c9 = 6 -> r9c3 = 2, r3c3 = 6

Straightforward from here with singles and cage combinations.
Very Happy

Andrew has pointed out some things that ought to be clarified but I don't have time to check it through now. Some time soon hopefully.


Last edited by CathyW on Tue Nov 20, 2007 10:01 am; edited 1 time in total
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Para
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PostPosted: Fri Nov 09, 2007 10:11 pm    Post subject: Reply with quote

mhparker wrote:
Unfortunately it doesn't help: I'm still in the "relegation zone"... Sad


You could always catch up by posting a message at midnight saying that the assassin looks great and you can't wait to solve it. Wink

Para

ps. Do you think there is a benchmark at 350 messages?
pps. On the TJK 32: i think there wil be a time when everyone feels up for it, but not me right now, still cleaning up the debris of the brick wall. Just look how long it took us to tackle TJK 18.
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mhparker
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PostPosted: Fri Nov 09, 2007 11:08 pm    Post subject: Reply with quote

Hi Para,

Para wrote:
You could always catch up by posting a message at midnight saying that the assassin looks great and you can't wait to solve it. Wink

Or, (if I'm feeling particularly lazy), I could post a message at midnight saying that the Assassin looks great and I can't wait until Cathy solves it... Smile

Para wrote:
ps. Do you think there is a benchmark at 350 messages?

Good question. What comes after Grandmaster? Great-Grandmaster (a bit like great-grandfather) perhaps? Smile

Para wrote:
still cleaning up the debris of the brick wall.

Me too. Think I've already spent longer on your step 31 alone than you just did solving the complete A76!! Wink
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Mike
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gary w
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PostPosted: Sat Nov 10, 2007 12:17 am    Post subject: assassin 76 Reply with quote

Thought I would post my solution..at least it's brief!



Some prelims..

1.r5c46=6 4/5
2.r39c7=10 <>5 <>{19}
3.r158c6=11 and with r1c6=4 min r8c6<>789
4.r4c37=15
5.r8c37=7 c46=8
6.r5c37=9 (because of 4. and 1. above) <>{45} blocked by 1. above
7.Outies on N9=15

Now look at c7.
Both 5 and 9 can only be at r12 or 6.(9 cannot be at r4 because of a combo conflict with the 17(3) cage N4. viz; r4c7=9 -> r4c3=6 -> r5c6=1 and so r5c4=5 -> conflict in 17(3) cage.)
If 5 is at r6c7 9 is in r12c7 -> r1c6<>4 -> r8c6<>6 (using 3 above)..but then cannot fulfil requirements for 16(4) cage N69..no combo will do.
Therefore r6c7<>5 so 5 is in r12c7 -> r12c7<>9 (would -> r1c6=3 )
Therefore HS in c7 r6c7=9 -> r78c7=4{1/2} Thus 9(3) cage N69={234}
-> r6c8=4 r8c6=2 r8c4=6 so r8c7=4 (not 1..5. above) r7c7=1 r8c3=3.

Some work to do but it's all over now.



Not too much "crunching" this way.

Regards

Gary
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Caida
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PostPosted: Sat Nov 10, 2007 2:14 am    Post subject: Reply with quote

Hello all,

CathyW wrote:

I'm sure some of the 'new kids on the block' will be catching me up very soon with the first posts. Welcome to you all. Smile


Cathy, As one of the "new kids", thank you for the welcome Very Happy

I doubt very much that I will be one making a run for your record of first posts. For one thing I am still slow solving these killers and I find actually writing the walkthroughs slows me down even more. I just did the current puzzle in about an hour but must have screwed something up as I wind up with more 4s than I can use Embarassed

edited to add: I realize that 1 hour isn't slow to complete a puzzle - but it was one hour to get to an incorrect solution. If I want a correct solution I have to slow down and figure out what I'm doing and if I write the walkthrough I slow down even more. It wasn't my intention to have it sound like one hour was a slow time for an assassin - sorry if it came off that way!

I'm going to resist looking at the walkthroughs until I manage to figure it out - I feel that I am very close - and writing the walkthrough for myself really makes me think about what I'm doing. Perhaps in a few months I will be able to speed up.

Gary wrote:

P.S. Have had a look at the jigsaw killer no.32.No wonder noone has posted a wt!!whew...anyone thinking of starting a tag.??


I worked and worked on that particular puzzle for months. While I was lurking on the forums the first thing I did each time I entered the forum was to check to see if some kind soul had posted the walkthrough yet to put me out of my misery.

I've scrapped all my work on it - but remember that I did have a fairly solid start - I could try and create the start of a walkthrough this weekend. Then perhaps someone more adept at these puzzles would be kind enough to take over?
edited to add: I've posted my first 7 steps for TJK #32 - would love if someone could take a crack at the next steps! Smile


Right now I am going to go back and unravel the mess I have made of #76. Doubt that I will come up with anything not already posted in terms of a walkthrough - but if I do I will be sure to share it.
edited to add: I've finished 76 - I think my walkthrough looks different - but think it must be because I over-complicated things - so not sure if any point in posting - seeing as there are already some great walkthroughs already posted.


Caida
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Para
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PostPosted: Sun Nov 11, 2007 12:29 am    Post subject: Reply with quote

Caida wrote:
edited to add: I've finished 76 - I think my walkthrough looks different - but think it must be because I over-complicated things - so not sure if any point in posting - seeing as there are already some great walkthroughs already posted.


You could always post your walk-through if you want some pointers on how you solved the puzzle. Just to un-complicate things a bit.

greetings

Para
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Caida
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PostPosted: Sun Nov 11, 2007 2:54 am    Post subject: Reply with quote

Para wrote:
You could always post your walk-through if you want some pointers on how you solved the puzzle. Just to un-complicate things a bit.


I would be delighted to receive any pointers. Very Happy

Here is my walkthrough: (edited from pointers received from Andrew and Para - thanks!!!)

Assassin 76

Prelims

a. 9(2)n1 = {18/27/36/45} (no 9)
b. 7(2) n3 = {16/25/34} (no 7..9)
c. 19(3)n3 = {289/379/469/478/568} (no 1)
d. 14(4)n36 = {1238/1247/1256/1346/2345} (no 9)
e. 9(3)n69 = {126/135/234} (no 7..9)
f. 6(2)n7 = {15/24} (no 3,6..9)
g. 20(3)n8 and n9 = {389/479/569/578} (no 1,2)
h. 15(2)n9 = {69/78} (no 1..5)


1. 20(3)n9 = {569/578} (no 3,4)
Note: combos {389} and {479} blocked by 15(2)n9
1a. -> 5 locked within 20(3)n9 for n9
1b. -> {69} and {78} locked in 20(3)n9 and 15(2)n9 for n9
1c. -> r7c789 and r8c7 (no 5..9)
1d. r6c8 no 1

2. Innies n2: r1c46 = 13(2) = {49/58/67} (no 1..3)

3. Innies n5: r5c46 = 6(2) = {15/24} (no 3,6..9)

4. Innies r1234: r4c37 = 15(2) = {69/78} (no 1..5)

5. r5c37 = 9(2) = {18/27/36} no (4,5,9)
Note: derived from r5c46 = 6(2) (step 3) and r4c37 = 15(2) (step 4)
Note: {45} blocked by h6(2) from step 3

6. 17(3)n45 = [971]/[962]/[935]/{78}[2]/{67}[4]
6a. -> r5c3 no 1,2
6b. cleanup: r5c7 no 7,8; [872] blocked by r5c37

7. 13(3)n56 = [913/841/751/823/742/652/643]
7a. -> r5c7 no 6
7b. cleanup: r5c3 no 3 -> eliminates [935] option for 17(3)n45
7c. -> r5c4 no 5
7d. cleanup: r5c6 no 1 -> eliminates [913] option for 13(3)n56
7e. -> r4c7 no 9
7f. cleanup: r4c3 no 6

missed in original walkthrough (pointed out by Para) [751/742] blocked by r5c46


8. Innies n8: r8c46 = 8(2) = {17/26/35} (no 4,8,9)

9. Innies r89: r8c37 = 7(2) = {16/25/34} (no 7..9)
Note derived using r8c46 from step 8
9a. r8c3 no 1,2

10. Looking at 12(3)n4 combo {129} and 6(2)n7 and h6(2)r5
10a. -> r6c1 no 9
10b: -> r5c2 no 9

11. Outies c12: r39c3 = 8(2) = {17/26/35} (no 4,8,9)

12. Outies c89: r39c7 = 10(2) = {28/37/46} (no 1,5,9)
12a. ->r3c7 no 6,7,8
12b. 5 locked for c8 in r89c8
12c. -> 20(3)n9 from step 1 r89c8 no 6
12d. cleanup: r1c9 no 2

13. 19(3)n3 = [2]{89}/[3]{79}/[4]{69}/[4]{78}
13a. r23c8 no 2,3,4


14. Outies c123: r158c4 = 16(3) = [916/817/925/826/943/547/745]
14a. -> r1c4 no 4,6
14b. -> r8c4 no 1,2
14c. cleanup: r1c6 no 7,9
14d. cleanup: r8c6 no 6,7
Para pointed out -> [817/925] blocked by r158c6

15. 17(3)n23 option {179} not possible
15a. r12c7 no 1

16. 16(4)n689 = [9]{124}/[8]{125}/[8]{134}/[7]{135}/[6]{145}/[7]{234}/[6]{235}
16a. r6c7 no (1..5)
16b. 5 locked in c9 for n6
16c. cleanup: r1c8 no 2

17. 5 in n3 locked in 17(3)n23 in r12c7
17a. 17(3)n23 = {458}
17b. -> r1c6 no 5,6 (5 must be in r12c7)
17c. -> r12c7 no 2,3,6,7,9
17d. 9 locked in n3 in r23c8
17e. HS r6c7 = 9
Para pointed out: r1c89 no 4; r1c89 = {16}

18. 16(4)n689 = [9]{124}
18a. -> r78c7 no 3; r8c6 no 3,5
18b. cleanup: r8c4 no 3,5
18c. cleanup: r8c3 no 4
18d. 4 locked for c7 and n9 in r78c7
18e. r1c6 = 4; r1c4 = 9
18f. {58} locked in c7 and n3 r12c7

19. 19(3)n3 = [3]{79}; {79} locked for c8 and n3
19a. 7(2)n3 = {16}; {16} locked for r1 and n3
19b. {24} locked in n3 in r23c9 for c9 also locked for 14(4)n36

20. 9(2)n1 = {27} locked for r1 and n1

21. 13(3)n56 = [652/751]
21a. -> r5c6 = 5
21b. -> r5c4 = 1
21c. 13(3)n56 = [652]
21d. 17(3)n45 = [971]
21e. r9c7 = 7

22. 15(2)n9 = {69}; locked for c9
22a. 7(2)n3 = [61]

23. 9(3)n69 = [423]
23a. 16(3)n6 = [385]
23b. r4c89 = [17]
23c. HS r5c5 = 9

24. 12(3)n4 = {46}[2]; {46} locked for n4
24a. r8c6 = 2
24b. r8c4 = 6
24c. r8c37 = [34]
24d. 15(2)n9 = [96]
24e. 9(2)n1 = [72]
24f. 6(2)n7 = {15}; locked for c1 and n7
24g. HS r4c2 = 5
24h. r9c3 = 2
24i. r89c2 = [78]

25. 14(3) n5 = {248}; locked for r4 and n5
25a. r4c1 = 3

26. everything now falls into place with cage sums and singles


Last edited by Caida on Tue Nov 27, 2007 10:09 pm; edited 2 times in total
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mhparker
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Joined: 20 Jan 2007
Posts: 345
Location: Germany

PostPosted: Wed Nov 14, 2007 9:23 pm    Post subject: Never Say Never Again Reply with quote

Hi folks,

Hmm, it's very quiet around here! Silenced Need to re-evaluate... Think

I (on the A71 thread) wrote:
I will not be posting any further variants on this forum

Well, that was the great idea. Unfortunately, as is often the case, things didn't quite turn out the way I planned. Therefore, I've decided to put the M2 on hold for a short while, and post a variant of the A76 that I've been enjoying working on for the last couple of days instead.

This puzzle may not be the "non plus ultra" as far as advanced techniques are concerned. You probably won't find any X-Cycles here, for example (or at least, I didn't find any!). Instead, what you should find is a good ol' traditional Killer. But, as Para said on the M1 thread: just because a puzzle requires only "basic" killer techniques doesn't mean to say it isn't hard... Wink


Assassin 76X (Est. rating: 1.5)



3x3:d:k:3072:3072:4098:4098:5124:2821:2821:3591:3591:5897:1546:4098:5124:5124:5124:2821:2832:4625:5897:1546:1546:5141:5141:5141:2832:2832:4625:5897:5897:3869:3358:3358:3358:3873:4625:4625:4132:4132:3869:3869:6440:3873:3873:3883:3883:4132:3886:5167:6440:6440:6440:4915:5428:3883:3886:3886:5167:3129:3129:3129:4915:5428:5428:1599:5184:5167:5167:5955:4915:4915:3910:1095:1599:5184:5184:5955:5955:5955:3910:3910:1095:

Note: It's a Killer-X, where no repeated digits are allowed on either diagonal.

Hope you like it!
_________________
Cheers,
Mike
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