Assassin 52

[Ruud]

A few minutes before Assassin 52 V1 is available, here is a V2 that will compensate the missing A51V2.



3x3::k:4608:46081794:589217972055:4617:46082571:589233426673:4617:4617:4617:4373:58926673:6673:66735404:4373:4373:58922839:51543099:5404:5926:5926:5926:5926:5926:51543099:54043119:5425:4658:4658:51546198:6198:61985425:4658:4924:4924:4924:6198160154253908492426242634:54252381:3910

Probably a Tag Team challenge

Ruud

[CathyW]

I can work out r5c5 - does that help!?

Bedtime for me now - will have to wait until tomorrow for the V1!

[Andrew]

I can work out r5c5 - does that help!?

Bedtime for me now - will have to wait until tomorrow for the V1!

I guess that applies for both V1 and V2

Sleep well!

[CathyW]

V1 relatively straightforward. Good job it's a bank holiday weekend in the UK - an extra day off to contemplate the V2!

1. Innies c5: r5c5 = 5

2. 16(2) r2c67 = {79}, 16(2) r9c67 = {79} (x-wings on 7 and 9) -> 7, 9 not elsewhere in r29 or c67.

3. Innies N1: r12c3 = 11 = [92/83/74/65]
Outies N1: r12c4 = 11 = [92/83/74/65]

4. Innies N3: r12c7 = 10 = [37/19]
Outies N3: r12c6 = 11 = [29/47]

5. Innies N7: r89c3 = 7 = {16}/{34}/[25]
Outies N7: r89c4 = 12 = [93]/{48}/[75] -> r8c3 <> 4, r9c3 <> 3

6. Innies N9: r89c7 = 15 = [69/87]
Outies N9: r89c6 = 12 = [39/57]

7. Innies N4: r456c3 = 14

8. Innies N6: r456c7 = 14

9. Outies c12/Innies c3: r37c3 = 13 = {49/58/67}

10. Outies c89/Innies c7: r37c7 = 6 = {15/24}

11. 8(3) in N1 must have 1, not elsewhere in N1.

12. 26(4) r1234c5 can't have 1 -> 1 locked to r3c46 -> not elsewhere in r3: r3c7 <> 1 -> r7c7 <> 5.

13. Innies r1234: r4c1289 = 10 = {1234}
-> r4c1 = 3/4 -> 20(3) r456c1 = 389/479 -> 9 locked to r56c1, not elsewhere in c1/N4.
-> r4c3 = 5678, r4c45 = {6789}, r4c6 = 68, r4c7 = 568 -> combinations for 14(3) r3c6+r4c67 -> r4c7 = 5, r3c6 = 1/3 -> split 6(2) r37c7 = {24} -> split 14(3) r456c7 = 5{36/18}

14. Innies r6789: r6c1289 = 26 (can't have 1)

15. Innies c1234: r5c34 = 3 = {12} -> r5c67 = 11 = {38} -> r5c1 <> 8 -> r5c2 = 4/6/7, r5c89 = {4679}

16. Outies - Innies N2: r4c5 - r3c46 = 3
a) if r4c5 = 6, r3c46 = [21]
b) if r4c5 = 7, r3c46 = {13}
c) if r4c5 = 8, r3c46 = [41/23]
d) if r4c5 = 9, r3c46 = [51]
-> candidates for r3c4 = 1/2/3/4/5

17. 11(3) r6c67 + r7c6 = 128/146/236 -> HS r8c6 = 5
-> r8c7 = 6, r9c6 = 7, r9c7 = 9, r2c6 = 9, r2c7 = 7
-> r1c6 = 2, r1c7 = 3 -> r5c7 = 8, r5c6 = 3
-> r6c7 = 1 -> r67c6 = {46} -> r4c6 = 8, r3c6 = 1
Clean up from placements: 15(2) r1c34 = [96]/{78}; 7(2) r2c34 = [25]/{34};
10(2) r8c34 = [19/28]; 9(2) r9c34 = [63/54]

18. NP {12} r58c3, not elsewhere in c3 -> r2c3 <> 2 -> r2c4 <> 5, r1c4 <> 6, r1c3 <> 9
-> 7(2) r2c34 = {34} not elsewhere in r2, 15(2) r1c34 = {78} not elsewhere in r1, 8(3) in N1 = {125} not elsewhere in N1

19. NP {34} r29c4, not elsewhere in c4 -> r3c4 = 5 -> r4c5 = 9 -> r4c34 = {67} -> split 13(2) r37c3 <> {67}

20. HS r5c4 = 1 -> r5c3 = 2, r4c2 = 1 -> r1c1 = 1, r1c2 = 5, r2c2 = 2 … lots of singles

[Para]

Hi all

I agree with Cathy, relatively straightforward. Nothing spectacular, one nice move i hoped to put to use in a walk-through for once. (Not that it was actually necessary, but sometimes it can break open puzzles, like one of my V2's)

Walk-through assassin 52

1. 45 on C5: 1 innie: R5C5 = 5

2. 8(3) in R1C1 = {125/134}: no 6,7,8,9; 1 locked for N1

3. R1C34 = {69/78}

4. 26(4) in R1C5 = {2789/3689/4679}: no 1; 9 locked for C5

5. R1C67 = {14/23}

6. Deleted: useless step

7. R2C34 = {25/34}/[61]: no 7,8,9; R2C4: no 6

8. R2C67 = {79}: locked for R2

9. 20(3) in R4C1 = {389/479/569/578}: no 1,2

10.11(3) in R4C2 and R6C6 = {128/137/146/236/245} : no 9

11. 19(5) in R5C3 = 5{1238/1247/1346}: 1 locked for R5

12. R8C34 = {19/28/37/46}: no 5

13. R8C67 = {29/38/47/56}: no 1

14. R9C34 = {18/27/36/45}: no 9

15. R9C67 = {79}: locked for R9
15a. Clean up: R9C34: no 2

16. 45 on N1: 2 outies: R12C4 = 11 = [65/74/83/92]: R2C4: no 1
16a. Clean up: R2C3: no 6
16b. CPE in 8(3) cage in R1C1 + 7(2) cage in R2C3: R2C1: no 2,3,4,5 (I love this move, it works because the combination of the 7(2) cage depends on the 8(3) cage, either way the cages contain the digits {12345})

17. 45 on N3: 2 outies: R12C6 = 11 = [29/47]: R1C6: no 1,3
17a. Clean up: R1C7: no 2,4
17b. 1in N2 locked for R3

18. 45 on N7: 2 outies: R89C4 = 12 = [48/75/84/93]: R8C4: no 1,2,3,6; R9C4: no 1,6
18a. Clean up: R8C3: no 4,7,8,9; R9C3: no 3,8

19. 45 on N9: 2 outies: R89C6 = [39/57]: R8C6 = {35}
19a. Clean up: R8C7 = {68}

20. 45 on R1234: 4 innies: R4C1289 = 10 = {1234}: no 5,6,7,8,9; {1234} locked for R4

21. 45 on R6789: 4 innies: R5C1289 = 26 = {2789/3689/4589/4679/5678}: no 1

22. Naked Pair {79} in R29C6: locked for C6

23. Naked Pair {79} in R29C7: locked for C7

24. 14(3) in R3C6 needs 2 of {568} in R4C67 -->> 14(3) = [185/365]: R3C6 = {13}; R4C7 = 5

25. 45 on N6: 2 innies: R56C7 = 9 = {18/36}: no 2,4

26. 11(3) in R6C6 needs one of {1368} in R6C7 -->> 11(3) = {128/146/236}: no 5
26a. R8C6 = 5(hidden single); R8C7 = 6; R9C67 = [79](step 19)
26b. R2C67 = [97]; R1C67 = [23](step 17)
26c. Clean up: R1C3: no 6; R2C3: no 5; R8C3: no 3; R8C4: no 4; R9C4: no 8(step 18); R9C3: no 1, 4

27. Naked pair {18} in R56C7: locked for C7 and N6
27a. R4C2 = 1(hidden single); R1C1 = 1(hidden single)

28. 17(3) in R4C8 = {269/467}: no 3; 6 locked for C8 and N6
28a. 3 in N6 locked for C9

Mistake in step 29. Edited from here on.

29. 11(3) in R6C6 = {146} (last possible combination)
29a. R6C7 = 1; R67C6 = {46}: locked for C6
29b. R5C7 = 8; R34C6 = [18]; R5C6 = 3
29c. R5C4 = 1(hidden single); R5C3 = 2; R8C34 = [19]; R9C34 = [63](step 18)

30. 18(3) in R3C4 needs 2 of {679} in R4C34 -->> 18(3) = [576](R3C4 = 5; R4C34 = [76])
30a. R4C5 = 9; R2C34 = [34]; R1C34 = [87]
30b. R123C5 = [683]; R12C2 = [52]; R2C1 = 6

31. R3C123 = {479}: locked for R3

32. 20(3) in R4C1 = [398] (last possible combination)

33. 19(3) in R8C2 = [748] (last possible combination): R8C2 = 7; R9C12 = [48]

And the rest is all singles.

greetings

Para

[Para]

Hi all

I just thought i would get the tag started(that way it looks like i contributed) because it doesn't seem i am going to solve this one by myself. This is the basic opening for Ass 52V2 that gets us 2 placements. I'll see if i can find anything else upcoming weekend. Time for me to do some work now.

Opening for Assassin 52V2:


1. 45 on C5: i innie: R5C5 = 1

2. R1C34 and R1C67 ={16/25/34}: no 7,8,9

3. 8(3) in R1C8 = {125/134}: no 6,7,8,9; 1 locked for N3
3a. Clean up: R1C6: no 6

4. R2C34 = {19/28/37/46}: no 5

5. R2C67 = {49/58/67}: no 1,2,3

6. 11(3) in R3C6 = {128/137/146/236/245}: no 9

7. 21(3) in R4C2 = {489/579/678}: no 1,2,3

8. 20(3) in R4C8 = {389/479/569/578}: no 1,2

9. 10(3) in R8C2 = {127/136/145/235}: no 8,9

10. R8C34 = {15/24}: no 3,6,7,8,9

11. R8C67 = {69/78}: no 1,2,3,4,5

12. R9C34 = {19/28/37/46}: no 5

13. R9C67 = {18/27/36/45}: no 9

14. 45 on N1: 2 outies: R12C4 = 8 = [17/26/53/62]: R1C4 = {1256}; R2C4 = {2367}
14a. Clean up: R1C3: no 3,4; R2C3: no 1,2,6,9

15. 45 on N3: 2 outies: R12C6 = 9 = [18/27/36/45/54]: R2C6: no 9
15a. Clean up: R2C7: no 4

16. 45 on N7: 2 outies: R89C4 = 5 = [14/23/41]: R8C4 = {124}; R9C4 = {134}
16a. Clean up: R8C3: no 1; R9C3 = {679}

17. 45 on N9: 2 outies: R89C6 = [67/76/85/94]: R9C6 = {4567}
17a. Clean up: R9C7: no 1,6,7,8

18. 45 on C12: 2 outies: R37C3 = 13 = {49/58/67}: no 1,2,3

19. 45 on C89: 2 outies: R37C7 = 10 = {28/37/46}/[91]: R3C7: no 5; R7C7: no 5,9

20. 45 on C1234: 2 innies = 15 = {69/78}: no 2,3,4,5

21. 45 on C6789: 2 innies = 7 = {25/34}: no 6,7,8,9

22. 45 on R1: 1 innie = 2 outies = R1C5 – R2C28 = 5: min R2C28 = 3 -->> min R1C5 = 8; Max R1C5 = 9 -->> Max R2C28 = 4 -->> R1C5 = {89} ;R2C28 = {12/13}: 1 locked for R2

23. 7 in R1 locked for N1
23a. Clean up: R2C4: no 3; R1C4: no 5(step 14); R1C3: no 2; R7C3: no 6(step 18)
23b. 7 in R1 locked in 18(3) cage in R1C1 -->> 18(3) = {79}[2]/{78}[3] -->> R1C12 = {789}; R2C2 = {23}
23c. R2C8 = 1(hidden single)

24. 45 on N4: 3 innies: R456C3 = 12: min R5C3 = 6 -->> max R46C3 = 6: no 6,7,8,9

25. 45 on R9: 1 innie – 2 outies = R9C5 – R8C28 = 1: max R9C5 = 9 -->> max R8C28 = 8: R8C8: no 8,9; R8C2: no 7; Min R8C28 = 3 -->> Min R9C5 = 4: no 2,3

26. Killer Pair {12} in R12C4 + R89C4: locked for C4

27. 12(3) in R6C3= {138/147/156/237/246/345} : no {129} : no{12} in R67C4 -->> R67C4: no 9

28. 45 on N6: 3 innies: R456C7 = 13

29. R456C3 = 12 = {129/138/147/156/237/246}
29a. 12(3) in R4C1: no {129} clashes with R456C3 -->> R456C1: no 9

30. R12C6: no [27]: clashes with R12C4
30a. Clean up: R1C7: no 5; R2C7: no 6


greetings

Para

[CathyW]

I wish you luck guys. I tried the V2 using JSudoku and Sumocue to see if it was really worth spending time on. Got two placements as did Para (including the obvious at r5c5). Neither JSudoku not Sumocue can make another placement without brute force so I'm pretty certain I can't either.

[mhparker]

Hi all,

just a quick post with another single move for the V2 (not the breakthrough, though ):

31. R1C2 and 21(3) at R4C2 form killer triple on {789} in C2 -> no 7,8,9 elsewhere in C2

More later, hopefully...

[Jean-Christophe]

I wish you luck guys. I tried the V2 using JSudoku and Sumocue to see if it was really worth spending time on. Got two placements as did Para (including the obvious at r5c5). Neither JSudoku not Sumocue can make another placement without brute force so I'm pretty certain I can't either.

Untrue with the upcoming version of JSudoku

The grid is solved !

Edit: removed JSudoku log

[CathyW]

I look forward to it JC.

There's a huge number of conflicting combinations for analysis in the log you provided. I'm not masochistic enough, nor do I really have enough time to spend on puzzles requiring such detail. Can mere mortals manage it without solver assistance? We'll see what Para, Mike and anyone else can come up with ...

[mhparker]

Here is the log without naked & hidden singles. I won't clean up the unnecessary moves. I've enough work with my own puzzles !

Bad move, JC, to post a JSudoku log whilst a tag solution is in progress. The whole point of a tag solution is that it should be a team effort, not an individual effort, as is usually the case with the V1's.

(Edit: Actually, as it turned out, the V2 wasn't very suitable for a tag solution, because it gave up too quickly. But, of course, I didn't know that at the time)

By all means, tell us in future right away if JSudoku can solve something, but please don't publish the log until we've found a solution (or given up trying to do so, as the case may be!). Thanks.

P.S. Yes, I'm very interested in the great work you've been doing, and look forward to analyzing the log, but only after trying a manual solution...

[mhparker]

Hi again,

Here's the next set of moves for the V2. The first move in the sequence cracks the puzzle. The rest should be just a formality now.

The puzzle wasn't anything like as difficult as the A48-Hevvie. This is because this puzzle was real close to caving in. Just needed one key move to topple it (see step 32 below).


32. Implication chain eliminates 8 in R2C3
32a. R2C3=8 -> R2C4=2 -> R2C1=3 -> R1C12={78} -> R2C3<>8 (contradiction)
32b. Conclusion: no 8 in R2C3
32c. Cleanup: no 2 in R2C4, no 6 in R1C4 (step 14), no 1 in R1C3

33. 1 in C3 now locked in N4, not elsewhere in N4
33a. 12/3 at R4C1 = {234|246|345} (no 8)

34. 1 in R1 locked in N2, not elsewhere in N2 (R3C6)
34a. min. R34C6 = 5 -> max. R4C7 = 6 (no 7,8)

35. 1 in N1 locked in 18/4 at R2C1 = {1269|1359|1368|1458}
35a. {1359} blocked by h9/2 at R12C3
35b. -> 18/4 at R2C1 = {1269|1368|1458}

36. deleted
37. deleted
38. deleted


Edit: walkthrough truncated after error at step 35a.
Fortunately, the error was after the breakthrough move...

[mhparker]

Post deleted.

[Jean-Christophe]

I look forward to it JC.

There's a huge number of conflicting combinations for analysis in the log you provided. I'm not masochistic enough, nor do I really have enough time to spend on puzzles requiring such detail. Can mere mortals manage it without solver assistance? We'll see what Para, Mike and anyone else can come up with ...

That's because it will exhaust all possible moves a technique may make before trying the next technique. It had to resort to several Complex XY-Chain to crack it. That's a new technique which is similar to mhparker's step 32.

Bad move, JC, to post a JSudoku log whilst a tag solution is in progress. The whole point of a tag solution is that it should be a team effort, not an individual effort, as is usually the case with the V1's.

By all means, tell us in future right away if JSudoku can solve something, but please don't publish the log until we've found a solution (or given up trying to do so, as the case may be!). Thanks.

P.S. Yes, I'm very interested in the great work you've been doing, and look forward to analyzing the log, but only after trying a manual solution...

OK I won't publish logs anymore. Anyhow, it's in tiny text and you don't have to read it!

Reading your walktrough, I cannot agree for step 35a:

35. 1 in N1 locked in 18/4 at R2C1 = {1269|1359|1368|1458}
35a. {1368} and {1458} blocked by h9/2 at R12C3

h9/2 in R12C3 = {36|45}
So we can't eliminate {1368} and {1458} here
However, we can eliminate {1359}

Should I continue ?
I'll use other step numbers
39. R1C3 = {56} -> 12/3 in R456C3 <> {156}
39a. h11/2 in R89C3 <> {56} = [29|47]
39b. 6/2 in R8C34 = {24} (NP @ R8)

40. Killer HP {56} in C3 locked in R1C3 or R37C3 -> 13/2 in R37C3 = {58}|[67]
40a. 6 of C3 locked in R13C3 for N1

41. Cage 12/3 in R456C1 = {237|246|345} = {(4|7)..}
41a. Cage 21/3 in R456C2 = {489|579|678} = {(4|7)..}
41b. Killer NP {47} @ N4 -> R456C3 <> {147} = {129|138}
41c. R46C3 = {123}, R5C2 = {89}
41d. cleanup R5C4 = {67} (NP {67} @ C4 with R2C4)

42. 9 of C4 locked in R34C4 -> Cage 17/3 in R34C4+R4C3 = {59}+3 (NP @ C4)
This unlocks the puzzle.


Edit fixed typos

[mhparker]

Reading your walktrough, I cannot agree for step 35a

Thanks for pointing that out, JC. I've withdrawn the later steps. I must have been quite tired when I wrote that!

I am simply concerned that early posting of JSudoku logs may discourage other members of the team from participating in a tag solution.